In the 3rd circuit, your transformation of V into I is wrong since the resistor and current source(transformed) are not in parallel. But you don't need a 3rd step. I think in the 2nd circuit itself, the answer is obvious (60V).jdawg said:
Vth, also known as the Thevenin voltage, is the voltage that would be measured across two terminals of a circuit when all the sources are removed and replaced by their internal resistances.
To calculate Vth, you need to first identify the open-circuit voltage across the two terminals of the circuit. This can be done by using source transformations to replace all the sources with their internal resistances. Then, the open-circuit voltage can be found by using Ohm's Law (V=IR) on the resulting circuit.
Rth, also known as the Thevenin resistance, is the equivalent resistance across two terminals of a circuit when all the sources are removed and replaced by their internal resistances.
To calculate Rth, you need to first identify the short-circuit current between the two terminals of the circuit. This can be done by using source transformations to replace all the sources with their internal resistances. Then, the short-circuit current can be found by using Ohm's Law (I=V/R) on the resulting circuit. Finally, Rth can be calculated by dividing the open-circuit voltage (Vth) by the short-circuit current (Isc).
Yes, source transformations can be used for any type of linear circuit. However, they are most commonly used for circuits that contain only independent sources (voltage or current) and resistors.