Special Relativity-Lorentz Transformation

In summary, the conversation discusses the concept of causally connected events, where one event may have caused the other. The condition for causality is expressed as |x| <= (+-) c*|t|, meaning that the events must be within the light-cone of each other. This condition is invariant for all inertial observers, and if two events are causally connected, all observers will agree on the order in which they occur.
  • #1
Qyzren
44
0
Can you guys please verify/help me with some questions.

Consider 2 events, A & B. In frame S they are separated by Δx and Δt. It is reasonable to say that the events are causally connected if it is possible for a signal (such as a light pulse) to travel between them. We mean that one might have caused the other. Write down a relation (an inequality) between Δx and Δt that expresses this. Make sure your relation is still valid when Δx and/or Δt are negative (hint: use absolute values)

I was thinking, since I = -(cΔt)² + (Δx)² + (Δy)² + (Δz)², with Δy and Δz = 0. We have I = -(cΔt)² + (Δx)²

Since this is a time like interval or at most light like interval, I <= 0.
so -(cΔt)² + (Δx)² <= 0.

I believe this should be correct but i didn't use any absolute value signs... or should i express it in terms of Δt & Δx instead of its square?


Show that the concept of being causally connected is invarient, i.e, that all inertial observers will agree on whether A & B are causally connected.
We have -(cΔt)² + (Δx)²
I define a new frame S', with interval (cΔt', Δx', Δy', Δz').
Δy' & Δz' is 0.
so using lorentz transformations:
x = γ(x'+vt), t = γ(t'+vx'/c²)
-(cγt' + γvx'/c)² + (γx' + γvt')² <= 0
some expanding & simplifying gives
γ²t'²(v²-c²) + γ²x'²(1-v²/c²) <= 0
subbing in γ² for c²/(c²-v²) for the first product and 1/(1-v²/c²) for the second gives
-(ct')² + (x')² <= 0.
Therefore all inertial observers will agree on whether A & B are causally connected.

Does this make sense? Or am i doing the question wrong?

Suppose that A & B are causally connected, and that A occurs before B in frame S, Show that all observers will agree that A occurs before B.

I am not so sure about this one, but i thinking...
Suppose there is a time t > 0 between events A and B (and a distance x),
i have to show that t' in any reference frame is > 0
that is to say, the time between the events is always positive, meaning A happened first.

Something along those lines, if someone could help me and check my answers, that would be great.
Thanks everyone for helping.
 
Physics news on Phys.org
  • #2
Hey,
Looks fine to me. Their reference to absolute values means that you can write your condition as
|x|^2 <= c^2*|t|^2
then taking square roots
|x|<= (+-) c*|t|.
Drawing a t vs. x diagram with event A at the origin, this condition means that event B is *within* the forward or backward lightcone of event A. A non-causally connected event B would be outside of the light-cone of A. (You can exchange A with B everywhere in those sentences).

Your thinking on the last question is also fine, keeping in mind the causality condition you found is satisfied (i.e., you may use the condition in your chain of reasoning).
 

FAQ: Special Relativity-Lorentz Transformation

What is the concept of Special Relativity?

Special Relativity is a theory developed by Albert Einstein in 1905 that explains how time and space are perceived differently for objects moving at different speeds. It also proposes the constant speed of light as a fundamental law of the universe.

What is the Lorentz Transformation?

The Lorentz Transformation is a mathematical formula used in Special Relativity to describe how time, space, and mass change for an object as it moves at high speeds. It allows for the prediction of these changes and has been proven to accurately describe the behavior of objects in motion.

How does Special Relativity affect our understanding of time and space?

Special Relativity states that time and space are not absolute, but are relative to an observer's frame of reference. This means that time can pass at different rates and distances can appear to be different depending on the speed and direction of an object's motion.

Can Special Relativity be applied to everyday objects and situations?

Yes, Special Relativity can be applied to everyday objects and situations, but the effects are usually only noticeable at extremely high speeds. For example, the difference in time measured by a clock on a moving airplane compared to a stationary clock on the ground is so small that it is negligible.

How does Special Relativity relate to the famous equation E=mc2?

E=mc2 is a consequence of Special Relativity and describes the relationship between energy, mass, and the speed of light. This equation shows that energy and mass are interchangeable and that a small amount of mass can produce a large amount of energy.

Similar threads

Replies
50
Views
2K
Replies
2
Views
2K
Replies
28
Views
632
Replies
14
Views
2K
Replies
1
Views
678
Back
Top