- #1
applestrudle
- 64
- 0
I am doing a presentation and want to make sure I'm not misunderstanding something very fundamental.
My argument goes like this:
t0 = ϒt
Santa is moving very fast and from his point of view he is in proper time. This means that if it takes him t0 seconds to deliver a present, the amount of time he observes passing on Earth is ϒt seconds and ϒt > t0.
This means on Earth it takes a lot longer to deliver all the presents (ϒt seconds) but for him it only takes t0 seconds. So he gets the job done in a shorter period of time.
Also, length contraction:
On Earth Santa needs to travel X m (X m is the distance between all the houses) but since he is moving so fast, the distance is reduced to
X0 = [tex] \frac{X}{\gamma}[/tex]
The two effects mean he has to travel a shorter distance and more time passes on Earth compared to the 12 hours in which he delivers the presents.
So he can successfully do the task.
My argument goes like this:
t0 = ϒt
Santa is moving very fast and from his point of view he is in proper time. This means that if it takes him t0 seconds to deliver a present, the amount of time he observes passing on Earth is ϒt seconds and ϒt > t0.
This means on Earth it takes a lot longer to deliver all the presents (ϒt seconds) but for him it only takes t0 seconds. So he gets the job done in a shorter period of time.
Also, length contraction:
On Earth Santa needs to travel X m (X m is the distance between all the houses) but since he is moving so fast, the distance is reduced to
X0 = [tex] \frac{X}{\gamma}[/tex]
The two effects mean he has to travel a shorter distance and more time passes on Earth compared to the 12 hours in which he delivers the presents.
So he can successfully do the task.