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Whatifitaint
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I have a simple question about special relativity time intervals.
Say when the origins of 2 frames are colocated, they sync their clocks to 0.
At time t1, frame 1 emits a light pulse. Then at time t2>t1 frame 1 emits a second light pulse. That is a time interval I in frame 1.
In frame 2, it receives these light pulses at times t1a' and t2a'. Then frame 2 does this calculation. At unknown time t1', the origin of frame 1 emits the light pulse. We have v*t1' = d1' as the distance the frame 1's origin traveled at the instant in frame 2's time at the 1st light wads emitted.
The travel time of the light pulse to reach the primed origin is d1'/c. So, t1a' = t1' + d1'/c.
Then, t1'a = t1' + t1'(v/c). Therefore, unknown t1' = t1'a/(1+(v/c)).
Also, t2' = t2'a/(1+(v/c)). Name this interval I' for t1' to t2'.
Question 1. Is the algebra right under special relativity?
Question 2. Does this mean time interval I occurs in frame 1 if and only if time interval I' occurs in frame 2?
Thanks
Say when the origins of 2 frames are colocated, they sync their clocks to 0.
At time t1, frame 1 emits a light pulse. Then at time t2>t1 frame 1 emits a second light pulse. That is a time interval I in frame 1.
In frame 2, it receives these light pulses at times t1a' and t2a'. Then frame 2 does this calculation. At unknown time t1', the origin of frame 1 emits the light pulse. We have v*t1' = d1' as the distance the frame 1's origin traveled at the instant in frame 2's time at the 1st light wads emitted.
The travel time of the light pulse to reach the primed origin is d1'/c. So, t1a' = t1' + d1'/c.
Then, t1'a = t1' + t1'(v/c). Therefore, unknown t1' = t1'a/(1+(v/c)).
Also, t2' = t2'a/(1+(v/c)). Name this interval I' for t1' to t2'.
Question 1. Is the algebra right under special relativity?
Question 2. Does this mean time interval I occurs in frame 1 if and only if time interval I' occurs in frame 2?
Thanks