- #1
benworld
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Homework Statement
A stoppered bottle, weights 38.215 g when empty , weights 45.362 g when filled with water. When filled with unknown liquid the bottole and unknown weighs 44.221 g. Calculate the liquid's specific gravity :
Homework Equations
D = m / v
s.g.. = density of unknown / density of water
The Attempt at a Solution
Density of water = 1 g/ml
m = 44.221 g - unknown
v = 44.21 - 38.215 = 6.00 ml
d = m /v
d = 44.221 / 6.00 = 7.362 g/ml unknown
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Fiding density of water
v = 45.362 g - 38.215 g
v = 7.147
d = 45.362 / 7.147 = 6.347 g
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Specific Gravity
= 7.362 g/ml 6.347 g/ml = 1.160 g/ml
is the answer 1.160 g/ml ? Correct or wrong ?