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Lunar Guy
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[SOLVED] Specific heat capacity (Calorimetry)
When a driver brakes an automobile, friction between the brake disks and the brake pads converts part of the car's translational kinetic energy to internal energy. If a 1500 kg automobile traveling at 32 m/s comes to a halt after its brakes are applied, how much can the temperature rise in each of the four 3.5 kg steel brake disks? Assume the disks are made of iron [tex](c_{p} = [/tex] 448 J/kg•°C) and that all of the kinetic energy is distributed in equal parts to the internal energy of the brakes.
[tex]c_{p,x}m_{x}T_{x}[/tex] = [tex]c_{p,y} m_{y} T_{y}[/tex]
I really don't know where to start with this problem... A little push and I can do the rest, but...
[tex]c_{p,x}m_{x}T_{x}[/tex] = [tex]c_{p,y} m_{y} T_{y}[/tex]
Homework Statement
When a driver brakes an automobile, friction between the brake disks and the brake pads converts part of the car's translational kinetic energy to internal energy. If a 1500 kg automobile traveling at 32 m/s comes to a halt after its brakes are applied, how much can the temperature rise in each of the four 3.5 kg steel brake disks? Assume the disks are made of iron [tex](c_{p} = [/tex] 448 J/kg•°C) and that all of the kinetic energy is distributed in equal parts to the internal energy of the brakes.
Homework Equations
[tex]c_{p,x}m_{x}T_{x}[/tex] = [tex]c_{p,y} m_{y} T_{y}[/tex]
The Attempt at a Solution
I really don't know where to start with this problem... A little push and I can do the rest, but...
[tex]c_{p,x}m_{x}T_{x}[/tex] = [tex]c_{p,y} m_{y} T_{y}[/tex]
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