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Prototype07
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Homework Statement
The following data is obtained:
Weight of ice cube added 20 g
Weight of copper calorimeter 80.5 g
Weight of water in calorimeter 105 g
Initial temp of ice cube -18 deg C
Initial temp of water 23 deg C
Final temp of water 6 deg C
Specific Heat Capacity copper 385 J kg-1K-1
Specific Heat Capacity water 4185 J kg-1K-1
Specific Latent Heat Fusion of Ice 335 kJ kg-1
Calculate a value for the Specific Heat Capacity of ice in J kg-1K-1.
Homework Equations
Q= Mass x Specific Heat Capacity x change in temperature
The Attempt at a Solution
I've tried countless attempts and literally spent hours trying to work this out, all have pointed to dead ends and I really don't know what else to try...
20g = 0.02kg
335kJ = 335000 J
105g = 0.105kg
(0.02kg x 335000J kg-1) + (0.02kg x c) x (6 - -18) = (0.105kg x 4185J kg-1K-1) x (23 - 6)
6700 + (0.02 x c) x 24 = 439.425 x 17
6700 + (0.02 x c) x 24 = 7470.225
0.02 x c x 24 = 770.225
c = 770.225 / (0.02 x 24)
c = 1604.635 J kg-1K-1
Now, I need to work out the SHC of ice which, pre-calculations, we should know it as being around 2000-2100, right? So surely that should mean 1604 is incorrect?
I've really got no idea what to do anymore, should I have included the SHC of copper and the mass of the calorimeter into the equation somewhere too?
Any help would be appreciated!