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alexander_i
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Homework Statement
A snowmobile climbs a hill at 6.526m/s. The slope of the hill is a 1 ft rise for every 40 ft of distance. The resistive force of the snow is equal to 3.3 percent of the weight of the snowmobile. How fast will the snowmobile move downhill, assuming the engine delivers the same power?
Homework Equations
Would the resistive force be .033*mg, or .033*mg*cos[tex]\theta[/tex]
The Attempt at a Solution
Fd = Driving force, P=F*v -> F=P/v
Fr = Resistive force
Up the hill: ma=0=Fd-mgcos[tex]\theta[/tex] -Fr
Fd= mgcos[tex]\theta[/tex] + Fr
Down: ma= Fd + mgcos[tex]\theta[/tex] - Fr
-I'm confused if they want the final velocity (due to acceleration) or if madown = 0?
if it's the final V, then I need vf = vo +at,
where I can find t with the quadratic equation by: X= Vo*T + [tex]\frac{1}{2}[/tex]a*T2
I'll also try by means of energy, but I still need to know about the resistive forge :\
Thanks for your help in advance.
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