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lowcard2
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Homework Statement
Two stationary positive point charges, charge 1 of magnitude 3.55 and charge 2 of magnitude 1.60 , are separated by a distance of 55.0cm. An electron is released from rest at the point midway between the two charges, and it moves along the line connecting the two charges.
What is the speed of the electron when it is 10.0 from charge 1?
The attempt at a solution
Fnet = kQe/r² - kqe/r² = [(9x10^9)(1.6x10^-19)/0.275²][3.8 - 2]x10^-9
Fnet = 3.71x10^-17
a = Fnet/m = 4.076x10^13
t² = 2ax = 2.855x10^6
t = (10^6)√6.32 = 2.855x10^6 m/s
v(x) = 2.855x10^6 m/s x 4.076x10^13
but answer doesn't make sense
thank you all for your time