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Islam Hassan
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The speed of light is a parameter that attaches itself to what exactly, an inertial frame of reference or a massless particle moving therein?IH
Islam Hassan said:The speed of light is a parameter that attaches itself to what exactly
Very interesting question, I'd like to have a go at answering this. Space-time itself specifies a top speed (possibly infinite), whereas Maxwell's equations tell us what the speed of EM waves is (so this determines the speed of light, c).Islam Hassan said:The speed of light is a parameter that attaches itself to what exactly, an inertial frame of reference or a massless particle moving therein?
IH
I'm not sure how to answer a question like "If the photon had mass . . .".wabbit said:Hmm is that right ? If the photon had mass wouldn't this modify Maxwell's equations ? And if it is massless it must travel at the invariant speed. I may be wrong here but I think Maxwell's equations as such are only compatible with the speed of light being both finite and equal to the invariant speed, no ?
Trying to recall SR derivation here, I think it goes Maxwell -> invariant speed of light -> SR with top speed =speed of light.
The value of c is entirely determined by your system of units. What matters is whether or not the invariant speed (aka c) is finite. If it is infinite then you get Galilean relativity, and if it is finite then you get Einstein's relativity.Islam Hassan said:Is it theoretically possible to have a different "species" of spacetime (alternative universes and the like...) where c has a different value?
Islam Hassan said:is the speed of light a constant ascribed to the i) the movement of a particle proper due to inherent characteristics of this particle or some property of spacetime that puts a limit on the speed of this movement?
Playing devil's advocate, we don't measure spacetime. How is it certain it's a property of spacetime itself.PeterDonis said:As I said in post #3, it's a property of spacetime.
nitsuj said:we don't measure spacetime.
nitsuj said:How is it certain it's a property of spacetime itself.
PeterDonis said:We measure the motion of freely falling objects, which marks out the geodesics of spacetime and tells us its geometry. That amounts to measuring spacetime, at least in the required sense for this discussion.
PeterDonis said:Because all massless particles travel at the same speed. If it were a property of particles, we would expect to see different values of ##c## for different particles and different interactions.
nitsuj said:The choice to use the phenomenon of a geodesic as describing the geometry of spacetime is just that...a choice.
nitsuj said:It is also that gravity is a field
nitsuj said:To be clear the difference here is "Spacetime limits propagation of fundamental forces." vs "Fundamental forces have a property; propagating at an invariant speed."
nitsuj said:They've tried to directly measure spacetime (in this context), but failed.
PeterDonis said:But on the second interpretation, there is no reason to expect all fundamental interactions to propagate at the same invariant speed. There could be more than one. Only if the invariant speed is a property of spacetime, not the forces, would you expect it to be the same for all interactions.
(Of course, trying to model different invariant speeds for different interactions would require a very different model from the ones we're used to. But so what? Such a model is still logically possible.)
PeterDonis said:Can you give a reference? I don't understand what you're referring to here.
nitsuj said:For my "daily experience" why would I see a difference if the fundamental forces had different speeds?
nitsuj said:Was referring to theories & experiments regarding the invariance of light, looking for properties specific to spacetime, like aether.
PeterDonis said:You probably wouldn't in your daily experience, but it would be straightforward (though possibly technically quite challenging) to do experiments to show the different speeds if they existed.
PeterDonis said:These experiments were looking for a preferred frame, which could be interpreted as a "property of spacetime", but is certainly not the only possible one.
nitsuj said:what of a "force carrier" that can go faster then another type of "force carrier" in order to accelerate a bit of matter faster than the interaction that caused that effect of more velocity?
PeterDonis said:we are getting pretty far off topic at this point.
I think you might like the (less well-known) derivations of SR that don't assume the light principle, (which I'm guessing you're not already familiar with?). Cf. Rindler's SR textbook (and various others -- I could dig out more specific references if needed).wabbit said:Trying to recall SR derivation here, I think it goes Maxwell -> invariant speed of light -> SR with top speed =speed of light.
would you have a reference/link ? I have a vague recollection of seeing that but can't remember where, nor the details.A more general analysis yields fractional linear transformations instead of the usual linear Lorentz transformations, and a universal length constant
strangerep said:It turns out that if we ask for the most general group of transformations compatible with the relativity principle (i.e., that all inertial observers perceive the same laws of physics), then a universal constant with dimensions of speed emerges as one possibility (among very few).
The properties of unitary irreducible representations (field representations) of the group then enables an identification between massless spin-1 reps and light. That enables the value of "c" to be identified with light speed empirically.
Pal's paper Nothing but relativity derives a general transform from the principle of relativity. The transform contains an unknown constant, K. There are only two "types" of value for K - zero and positive. The former gives you Newton; the latter gives you Einstein with [itex]K=1/c^2[/itex].nitsuj said:So what makes it "turn out" that given one SR postulate we can deduce a "universal constant with dimensions of speed" and is that the same as saying an invariant speed?
Ibix said:Pal's paper Nothing but relativity derives a general transform from the principle of relativity. The transform contains an unknown constant, K. There are only two "types" of value for K - zero and positive. The former gives you Newton; the latter gives you Einstein with [itex]K=1/c^2[/itex].
The paper uses nothing more complex than matrix multiplication.
I discussed it in more detail in various posts in this thread:wabbit said:would you have a reference/link ? I have a vague recollection of seeing that but can't remember where, nor the details.
It drops out of an analysis which asks for the maximal group of transformations which map inertial motion into inertial motion. Basically, it's from the assumption that velocity boosts in a fixed direction form a 1-parameter Lie group.nitsuj said:So what makes it "turn out" that given one SR postulate we can deduce a "universal constant with dimensions of speed" and is that the same as saying an invariant speed?
I'm not sure what you're disagreeing with here. The universal constant happens to be an upper limit on relative speed. It is found simply by looking for fixed points in the velocity boost composition formula that drops out of the analysis.It doesn't seem like it, just seems to say there would be a max speed and that's it.
"Force carriers" implies an interacting theory, but what I described is applicable to the simpler free case, i.e., transformations between inertial (unaccelerated) frames.My musing of it lead me to think it's implicit, that "force carriers" would move fastest and be an invariant speed, in turn coordinate transforms can be done and observation is continuity in causation.
IIRC, Pal uses some sleight of hand to dismiss the K<0 case. Actually, most treatments are a bit weak on that point.Ibix said:[Pal's] paper uses nothing more complex than matrix multiplication.
No. Spatial isotropy is an extra assumption. Spacetime homogeneity is also an addition assumption to reduce the fractional linear equations to linear equations. But in fact, that common form of the spacetime homogeneity postulate is unnecessary: the more general fractional linear case (not treated by Pal) yields a de Sitter space which has constant curvature. This is a more general version of the idea that space "looks the same" everywhere. I.e., spatial homogeneity (in the sense of constant curvature) need not be assumed.nitsuj said:Gave [Pal's paper] a reading, in that paper he mentions "Isotropy" & "homogeneity" of spacetime as being "given". Is that from the principal of relativity postulate?
strangerep said:No. Spatial isotropy is an extra assumption. Spacetime homogeneity is also an addition assumption to reduce the fractional linear equations to linear equations. But in fact, that common form of the spacetime homogeneity postulate is unnecessary: the more general fractional linear case (not treated by Pal) yields a de Sitter space which has constant curvature. This is a more general version of the idea that space "looks the same" everywhere. I.e., spatial homogeneity (in the sense of constant curvature) need not be assumed.
strangerep said:"Force carriers" implies an interacting theory, but what I described is applicable to the simpler free case, i.e., transformations between inertial (unaccelerated) frames.
strangerep said:I'm not sure what you're disagreeing with here. The universal constant happens to be an upper limit on relative speed. It is found simply by looking for fixed points in the velocity boost composition formula that drops out of the analysis.
It didn't seem tricksy to me (maybe I've fallen for it). He seems to be saying that if K<0 then it is possible to find frames where the transform does not reduce to the identity operation in the case of zero velocity. He notes that there are similar problems in the Einsteinian K>0 case for velocities greater than c, but observes that those frames are rendered inaccessible by the relativistic velocity addition law. In contrast, the velocity addition law for K<0 doesn't protect you from having to consider the problematic frames.strangerep said:IIRC, Pal uses some sleight of hand to dismiss the K<0 case. Actually, most treatments are a bit weak on that point.