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Vanessa23
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Homework Statement
A projectile is fired with an initial speed of 68 m/s at 37 degrees above horizontal on a flat firing range. c) Determine speed of the projectile 2.3 seconds after firing. d) Determine direction of projectile 2.3 s after firing.
Homework Equations
c) Vox=Vx=68m/s
Vy=Voy*sin(theta)-gt
V=sqrt(Vx^2+Vy^2)
d) tan^-1(Vy/Vx)= theta
The Attempt at a Solution
I got that Vx=68m/s
Vy=68*sin(37)-(9.8*2.3)
Vy=18.38
V=sqrt(68^2+18.4^2)
V=70.4
but the velocity is not 70.4 what am I doing wrong??
Thanks for any help!
The second part I get theta= 15.1 degrees but I don't want to submit it because if the first part is wrong then this is probably not right either.