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bec2008
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Homework Statement
A proton, initially at rest, is accelerated through an electric potential difference of 500V. What is the speed of the proton?
Homework Equations
V=k(q/r)
Solving for r: r=k(q/v)
v=d/t
known charge of a proton: 1.6E-19C
known value of k: 9E9Nm^2/C2
The Attempt at a Solution
I tried solving for r to get a distance.
r= (9E9Nm^2/C2)(1.6E-19C)/ 500V
r= 2.88E-12m
v=d/t
v= (2.88E-12m)/1 s
v= 2.88E-12 m/s
Our professor gave the answer as 3.1E5 m/s, but I cannot get to this answer. Any help would be greatly appreciated!