- #1
clickcaptain
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Could someone double check to make sure my calculations are all done right? I've done this problem several times and gotten the same answer but the online submission says its wrong so I need someone else to check my work. thanks!
x = ρ sin(Φ) cos(θ)
y = ρ sin(Φ) sin(θ)
z = p cos(Φ)
4z2 = x2+y2
4p 2cos2(Φ) = ρ 2sin2(Φ) cos2(θ) + ρ 2sin2(Φ) sin2(θ)
cos2(Φ) = (ρ 2sin2(Φ) cos2(θ) + ρ 2sin2(Φ) sin2(θ))/ (ρ 2 *4)
***(ρ2's cancel right?)****
so I'm left with for an answer
cos2(Φ) = (sin2(Φ) cos2(θ) + sin2(Φ) sin2(θ))/ 4)
Homework Statement
Homework Equations
x = ρ sin(Φ) cos(θ)
y = ρ sin(Φ) sin(θ)
z = p cos(Φ)
The Attempt at a Solution
4z2 = x2+y2
4p 2cos2(Φ) = ρ 2sin2(Φ) cos2(θ) + ρ 2sin2(Φ) sin2(θ)
cos2(Φ) = (ρ 2sin2(Φ) cos2(θ) + ρ 2sin2(Φ) sin2(θ))/ (ρ 2 *4)
***(ρ2's cancel right?)****
so I'm left with for an answer
cos2(Φ) = (sin2(Φ) cos2(θ) + sin2(Φ) sin2(θ))/ 4)