Spherical star in a hydrostatic equilibrium

In summary, the author is trying to solve an equation for a pertubation in the full momentum equation, but is not quite sure about it.
  • #1
ted1986
22
0
Hello again,

I've got a question about a star in a hydrostatic equilibrium.
How do I derive an equation of motion for a pertubation in the full momentum equation? I'm attaching my solution (my_solution.jpg) , but I'm not quite sure about it.

The full exercise is attached as astro_problem.jpg.

Thank you.
 

Attachments

  • astro_problem.jpg
    astro_problem.jpg
    36.7 KB · Views: 580
  • my_solution.jpg
    my_solution.jpg
    16.8 KB · Views: 586
Astronomy news on Phys.org
  • #2
It's not that simple, the meaning of "d" and "delta" are different. The meaning of "d" is "a change as you change location", but the meaning of "delta" is "perturbed from the original equation." So before you substitute and delta expressions, you first have to find the momentum equation that applies to the delta variables. When you're all done, you'll still have d/dr kinds of things, but they will apply to the delta variables, not the P and rho by themselves.
 
  • #3
I think I did this once. I even thought it was my idea. Don't use their hints, see attachment. The "del" works like del f = f' del r.
 

Attachments

  • dada.jpg
    dada.jpg
    14 KB · Views: 444
  • #4
Helios said:
I think I did this once. I even thought it was my idea. Don't use their hints, see attachment. The "del" works like del f = f' del r.



OK, I tried to solve the exercise as you said (P=K*rho^[tex]\gamma[/tex]), but the equaion I've got seems to be to complicated... (my derivation is attached - star_my_sol2.jpg)

Perhaps the derivation needed to solve it is less complicated?

Thank you.
 

Attachments

  • star_my_sol2.jpg
    star_my_sol2.jpg
    29.5 KB · Views: 443
  • #5
Sorry, but that's way off because the way you related density and mass. Your equation would only work for mean density, were M the total mass. Their relationship is instead differential.
The knack here is to apply the variation ( perturb ) and then factor out ( linearize ) the del-r out. Since the variation is arbitrary, the parenthetical stuff must equal zero ( the derived equation ).
I don't get the hints they gave.
 

Attachments

  • dada02.jpg
    dada02.jpg
    24.8 KB · Views: 471
  • #6
Thank you for your efforts :)
 

FAQ: Spherical star in a hydrostatic equilibrium

What is a spherical star in a hydrostatic equilibrium?

A spherical star in a hydrostatic equilibrium is a star that maintains a balance between the inward force of gravity and the outward pressure from the energy generated by nuclear fusion in its core. This equilibrium allows the star to maintain its spherical shape and prevents it from collapsing under its own gravity.

How does a spherical star achieve hydrostatic equilibrium?

A spherical star achieves hydrostatic equilibrium through the process of nuclear fusion. In the core of the star, hydrogen atoms fuse together to form helium, releasing a tremendous amount of energy in the process. This energy creates outward pressure that counteracts the force of gravity, keeping the star stable.

What factors affect the hydrostatic equilibrium of a spherical star?

The hydrostatic equilibrium of a spherical star is primarily affected by its mass and the rate of nuclear fusion in its core. Other factors such as temperature, density, and composition can also play a role in maintaining this equilibrium. Any changes in these factors can disrupt the balance and cause the star to expand or contract.

How long can a spherical star maintain hydrostatic equilibrium?

The duration of hydrostatic equilibrium in a spherical star depends on its mass and rate of nuclear fusion. Higher mass stars have a larger supply of fuel and can maintain equilibrium for millions or even billions of years. Lower mass stars, on the other hand, have less fuel and may only remain in equilibrium for a few million years.

What happens when a spherical star is no longer in hydrostatic equilibrium?

When a spherical star is no longer in hydrostatic equilibrium, it can either expand or contract, depending on the factors that caused the disruption. If the star's core runs out of fuel, it will collapse under its own gravity, leading to a supernova explosion. If the star gains more mass from a companion star, it may expand and become a red giant. Ultimately, the fate of the star will depend on its mass and other factors.

Similar threads

Replies
26
Views
4K
Replies
49
Views
4K
Replies
2
Views
1K
Replies
11
Views
1K
Replies
15
Views
8K
Replies
10
Views
3K
Replies
32
Views
6K
Back
Top