Spin-dependent Hamiltonian of two particles

In summary, two spin-half particles with spins S1 and S2 interact with a spin-dependent Hamiltonian H. The eigenstates and eigenvalues of H are found in terms of |m1,m2> where (hbar)m1 and (hbar)m2 are the z-components of the two spins.
  • #1
Jufro
92
8

Homework Statement


Two spin-half particles with spins S1 and S2 interact with a spin-dependent Hamiltonian H=λS1*S2 (the multiplication is a dot product and is a positive constant). Find the eigenstates and eigenvalues of H in terms of |m1,m2>, where (hbar)m1 and (hbar)m2 are the z-components of the two spins.


Homework Equations


Sx |m>=1/2(Sp-Ss) |m>
Sy |m>=1/2i(Sp+Ss) |m>
Sz |m>=(hbar)m |m>
Sp=(hbar)√[s(s+1)-m(m+1)]
Ss=(hbar)√[s(s+1)-m(m-1)]

The Attempt at a Solution


S1*S2=S1xS2x+S1yS2y+S1zS2z

S1x=S2x=S1y=S2y=0. I said this because the problem only mentioned z-component and most problems only talk about Sz.

H|m1,m2>=λSz1Sz1|m1,m2>

H |1/2,1/2> = λ*(hbar)^2 (1/2)(1/2) |1/2,1/2> = λ*(hbar)^2/4 |1/2,1/2>
H |-1/2,1/2> = λ*(hbar)^2 (-1/2)(1/2) |1/2,1/2> = -λ*(hbar)^2/4 |-1/2,1/2>
H |1/2,-1/2> = λ*(hbar)^2 (1/2)(-1/2) |1/2,1/2> = -λ*(hbar)^2/4 |1/2,-1/2>
H |-1/2,-1/2> = λ*(hbar)^2 (-1/2)(-1/2) |-1/2,-1/2> = λ*(hbar)^2/4 |-1/2,-1/2>

Is this my final answer? Am I close? Or was I completely off.
 
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  • #2
Jufro said:

Homework Statement


Two spin-half particles with spins S1 and S2 interact with a spin-dependent Hamiltonian H=λS1*S2 (the multiplication is a dot product and is a positive constant). Find the eigenstates and eigenvalues of H in terms of |m1,m2>, where (hbar)m1 and (hbar)m2 are the z-components of the two spins.


Homework Equations


Sx |m>=1/2(Sp-Ss) |m>
Sy |m>=1/2i(Sp+Ss) |m>
Sz |m>=(hbar)m |m>
Sp=(hbar)√[s(s+1)-m(m+1)]
Ss=(hbar)√[s(s+1)-m(m-1)]

The Attempt at a Solution


S1*S2=S1xS2x+S1yS2y+S1zS2z

S1x=S2x=S1y=S2y=0. I said this because the problem only mentioned z-component and most problems only talk about Sz.
Those are operators. You can't arbitrarily set them equal to 0.

H|m1,m2>=λSz1Sz1|m1,m2>

H |1/2,1/2> = λ*(hbar)^2 (1/2)(1/2) |1/2,1/2> = λ*(hbar)^2/4 |1/2,1/2>
H |-1/2,1/2> = λ*(hbar)^2 (-1/2)(1/2) |1/2,1/2> = -λ*(hbar)^2/4 |-1/2,1/2>
H |1/2,-1/2> = λ*(hbar)^2 (1/2)(-1/2) |1/2,1/2> = -λ*(hbar)^2/4 |1/2,-1/2>
H |-1/2,-1/2> = λ*(hbar)^2 (-1/2)(-1/2) |-1/2,-1/2> = λ*(hbar)^2/4 |-1/2,-1/2>

Is this my final answer? Am I close? Or was I completely off.
Read about the addition of angular momentum. For this problem, consider ##(\vec{S}_1 + \vec{S}_2)^2##.
 
  • #3
I get what you are saying about the operators. That was just a bad attempt at trying to simply the problem. I get that (S1+S2)^2 would yield the total spin, but how would that play into the Hamiltonian.
 
  • #4
Expand ##(\vec{S}_1 + \vec{S}_2)^2## it out. What do you get?
 
  • #5
Thank you, I had figured it out last night with your hint. The expansion leaves S1^2+S2^2+2S1S2. Then the dot product of S1S2 gave S1xS1y+S2xS2y+S1zS2z. The Z component was simple that was the m(hbar) and the x and y components I wrote in terms of the ladder operators. Thanks again :)
 

FAQ: Spin-dependent Hamiltonian of two particles

1. What is the Spin-Dependent Hamiltonian of Two Particles?

The spin-dependent Hamiltonian of two particles is a mathematical operator used in quantum mechanics to describe the total energy of a system consisting of two particles with spin. It takes into account the interaction between the spin states of the two particles and their spatial coordinates.

2. How is the Spin-Dependent Hamiltonian of Two Particles different from the regular Hamiltonian?

The regular Hamiltonian only considers the spatial coordinates of particles, while the spin-dependent Hamiltonian also takes into account the spin states of the particles. This makes it a more comprehensive and accurate description of the energy of a system with particles that have spin.

3. What factors affect the Spin-Dependent Hamiltonian of Two Particles?

The Spin-Dependent Hamiltonian is affected by the spin states of the particles, their spatial coordinates, and any external magnetic or electric fields present in the system. It also depends on the type of interaction between the particles, such as whether they are interacting through a potential or through exchange forces.

4. How is the Spin-Dependent Hamiltonian used in practical applications?

The Spin-Dependent Hamiltonian is used in a variety of practical applications, such as in magnetic resonance imaging (MRI) and nuclear magnetic resonance (NMR) spectroscopy. It is also used in the study of magnetic materials and in the development of spin-based technologies for quantum computing.

5. Can the Spin-Dependent Hamiltonian be solved analytically?

In most cases, the Spin-Dependent Hamiltonian cannot be solved analytically. Instead, it is solved numerically using various techniques such as perturbation theory, variational methods, and numerical diagonalization. However, for simple systems with known spin interactions, an analytical solution may be possible.

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