- #36
MeJennifer
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But there is!pervect said:There is certainly a circumference for the disk in a non-rotating Minkowskian frame. However, there isn't really any such thing as the circumference in a "rotating frame".
If you stand on the edge of a disk and I stand right next to you and you start to rotate on it and I stay inertial we will meet again.
Needless to say that we would not agree at all on both the duration and distance of the trip but nevertheless we would both agree our wordlines formed a closed loop!
The helix example shows something else, it shows that if we insist on splitting space-time in 3+1 for an observer on the disk we will have many troubles ahead to put it mildly.pervect said:And the helix example shows why. Or rather it should show why. You seem not to get the point I'm trying to make, and I don't understand the difficulty. And I don't seem to be able to think of a way to explain it better than I already have.
Actually I think do get your point but I am lost as to why your point has anything to do with: "...the "circumference" of the helix in the above article isn't really well defined, because it just isn't a geometrically closed object."pervect said:You seem not to get the point I'm trying to make, and I don't understand the difficulty.
It seems that your point is that there is no proper plane of simultaneity describing the complete ring (let alone the disk) for an accelerating observer on the ring, and thus one cannot calculate the circumference in terms of space only. And I do not disagree with that! I am fully aware of that.
But that does not mean that there is no circumference!
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