- #1
Koshi
- 18
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This is a physics problem, but I only need help with the calculus portion of it. I was having trouble figuring out how to split the integral to properly integrate.
[tex]\int[/tex][tex]\stackrel{\infty}{-\infty}[/tex](x/x_0)e-2|x|/x_0dx
where x_o is a constant
I was wondering how to write the lower part of the integral. What I have is
[tex]\int[/tex][tex]\stackrel{0}{-\infty}[/tex](x/x_0)e2x/x_0dx+[tex]\int[/tex][tex]\stackrel{\infty}{0}[/tex](x/x_0)e-2x/x_0dx
Is that right or should I keep the negative in front of the 2 in the lower integral?
Homework Statement
Homework Equations
[tex]\int[/tex][tex]\stackrel{\infty}{-\infty}[/tex](x/x_0)e-2|x|/x_0dx
where x_o is a constant
The Attempt at a Solution
I was wondering how to write the lower part of the integral. What I have is
[tex]\int[/tex][tex]\stackrel{0}{-\infty}[/tex](x/x_0)e2x/x_0dx+[tex]\int[/tex][tex]\stackrel{\infty}{0}[/tex](x/x_0)e-2x/x_0dx
Is that right or should I keep the negative in front of the 2 in the lower integral?