for second body diagram(m2) we replace all 1 with 2 and vice versaSuyash Singh said:
because the other mass is pulling it upChandra Prayaga said:
ummm i don't know.We never have practicals.Chandra Prayaga said:
haruspex said:
You do not know that yet. Just assign unknowns to the two string tensions, and do not assume the system is static.Suyash Singh said:
T2=m2gharuspex said:
No. For the third time, do not assume the system is static.Suyash Singh said:
Strings have this clever trick of carrying tension around corners and over pulleys.Suyash Singh said:
t1<m1gharuspex said:
oh i just saw photo of spring balanceharuspex said:
if its so then,Suyash Singh said:
No.Suyash Singh said:
The spring balance we are told is massless, and we can assume that its reading is constant. So its only functions in the question are to connect the two strings and to measure the tension in them. So apart from the measurement you can ignore the balance and treat the two strings as one.Suyash Singh said:
ok let acceleration of system be a(downwards of m1)haruspex said:
If two teams pull on a rope in a tug of war, each exerting 1000N of force, what is the tension in the rope?Suyash Singh said:
What standard equation are you using to get that, and to what free body are you applying it?Suyash Singh said:
1000N because they won't cancel out.jbriggs444 said:
i am applying it to both the massesharuspex said:
Right. So why do you think that the forces add in the situation for this problem?Suyash Singh said:
I asked what standard equation you are using. Please state it.Suyash Singh said:
standard equation:haruspex said:
i don't know the math here but in this case one of the force acts as a "support" ,that is, we could replace one of the force with a wall.jbriggs444 said:
but i don't know the math because its not given properly anywhere.Suyash Singh said:
Right. You have two equations and two unknowns. Solve to find the force.Suyash Singh said:
a=(m1-m2)g/m1+m2haruspex said:
that's why two teams pulling a rope with the same force of 1000N will produce a tension of 1000N !Suyash Singh said:
You missed out g and you should use parentheses in the denominator, but other than that, yes.Suyash Singh said:
A spring balance is a simple measuring device used to determine the weight of an object. It works by utilizing Hooke's law, which states that the force required to extend or compress a spring is directly proportional to the distance it is stretched or compressed. The spring balance consists of a spring attached to a hook on one end and a scale on the other. When an object is suspended from the hook, the spring stretches and the scale indicates the weight of the object.
The main difference between a spring balance and a regular scale is the mechanism used to measure weight. A regular scale typically uses a system of levers and counterweights, while a spring balance uses the principle of Hooke's law. Spring balances are also more portable and compact compared to regular scales.
The accuracy of a spring balance depends on the quality of the spring used and the design of the device. Generally, spring balances have a margin of error of around 1-2%. However, this can vary depending on the weight and size of the object being measured.
Yes, a spring balance can be used to measure other forces such as tension and compression. This is because the force required to extend or compress a spring is directly proportional to the distance it is stretched or compressed. However, the scale on a spring balance is calibrated to measure weight, so the readings may not be accurate for other forces.
The scale on a spring balance is typically marked with evenly spaced increments, usually in grams or Newtons. To read the measurement, simply note the number on the scale where the spring ends. This indicates the weight of the object in grams or Newtons.
