- #1
Ronnin
- 168
- 1
A spring with negligible mass and force constant of =400N/m is vert and a .2kg pan is suspended from its lower end. A butcher drops a 2.2kg steak onto the pan from a height of .4m. It makes a totally inelastic collision w/ the pan and sets the system into SHM.
A) What is the speed of the pan and steak immediatly after collision
Kf + Uf=Ki + Ui
v=(2gh)^1/2
v=2.8m/s
Vf=(m/M)Vm
(2.2/2.4)2.8=2.57m/s
This part I had no problems with, now
B) The amp of the subsequent motion
I can figure the KE of the system, but I know I must account for gravity in the PE as well as the spring's force. I know the compression of the spring due to gravity is mg/k which is .059m.
Spring PE=.5kx^2=.696J
KE=.5(2.4)2.57^2=7.926J
But a solution I saw actually subtracted the spring PE from the KE and got 7.34J total energy for the system. I thought total energy was PE + KE
A) What is the speed of the pan and steak immediatly after collision
Kf + Uf=Ki + Ui
v=(2gh)^1/2
v=2.8m/s
Vf=(m/M)Vm
(2.2/2.4)2.8=2.57m/s
This part I had no problems with, now
B) The amp of the subsequent motion
I can figure the KE of the system, but I know I must account for gravity in the PE as well as the spring's force. I know the compression of the spring due to gravity is mg/k which is .059m.
Spring PE=.5kx^2=.696J
KE=.5(2.4)2.57^2=7.926J
But a solution I saw actually subtracted the spring PE from the KE and got 7.34J total energy for the system. I thought total energy was PE + KE