Spring deflection load calculation for excavator

In summary, the hydraulic cylinder equipped with a helical coil compression spring is used to move the boom from position 1 to position 2. The maximum boom load in position 1 is 16550N and the minimum boom load in position 2 is 18550N. The spring load Fs1 for position 1 is 16454.48N and the spring load Fs2 for position 2 is 9500N. The oil pressure acting on the plate increases to push on the plate and the load forces are constant at the two positions.
  • #1
robax25
238
3
1. A hydraulic cylinder equipped with a helical coil compression spring(figure is attached). The oil pressure acts the spring and moves the boom from position 1 to position 2.

Maximum boom load in position 1 F1max= 16550N
Minimum boom load in position 2 F2min = 18550N

cylinder load Fcyl=19000N
Elastic modulus E= 206000N/mm^2
shear modulus G=80000N/mm^2

1)determine the springs Load Fs1 and Fs2 for the different boom positions.

Homework Equations



F=C/S C= spring constant, s= deflection of the spring

The Attempt at a Solution


Springs load Fs1 for the positions 1 Fs1=Fcylsin60° =16454.48N
spring load Fs2 for the position 2 Fs2 = Fclycos60°=9500N
 

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  • #2
What is the direction of gravity in this problem? Is it a factor? If so, do you have the weight of the boom? Is the shovel force constant in direction, fixed relative to the boom, or what? We seem to be missing some information here.
 
  • #3
yes, shovel force is constant. All descriptions can be found in the figures which I uploaded.
 
  • #4
robax25 said:
yes, shovel force is constant. All descriptions can be found in the figures which I uploaded.

So the shovel force is constant in both magnitude and absolute direction, or constant in magnitude and constant in relative direction?

I saw no gravity vector, so does that mean that gravity, and consequently weight, is not a factor?
 
  • #5
gravity is included. when it moves from neutral position it needs 19000 N force which is provided by hydraulic cylinder. In this case structure weight is neglected but shovel force has to be considered. from neutral position to position 1 is 30 degree and in this position shovel can take 16550N force(maximum) and when it moves back 30° from neutral position, it has minimum force 18550N.
 
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  • #6
robax25 said:
The oil pressure acts the spring and moves the boom from position 1 to position 2.
The oil pressure acting on the plate would move it from position 2 to position 1.

I don't understand how the oil pressure (Fcyl*area) can be constant. From an equilibrium state, it must increase to push on the plate.

I'm not sure in what sense the load forces are a max and a min. Max and min wrt what? Certainly not in respect of each other, since the min is greater than the max. Maybe just ignore those qualifiers and say those are the load forces at the two positions.
On that basis, and trusting the "constant Fcyl" statement, what is the corresponding spring force at each position?
 

FAQ: Spring deflection load calculation for excavator

1. How is the spring deflection load calculated for an excavator?

The spring deflection load for an excavator is calculated by using the formula F = kx, where F is the force applied to the spring, k is the spring constant, and x is the distance the spring is compressed or extended. This calculation helps determine the maximum load the spring can support without permanent deformation.

2. What factors affect the spring deflection load for an excavator?

The spring deflection load for an excavator is affected by several factors, including the type and material of the spring, the placement and orientation of the spring within the excavator, and the weight and force exerted on the excavator during operation. Other factors such as temperature and wear and tear can also impact the spring's ability to withstand loads.

3. How important is it to accurately calculate the spring deflection load for an excavator?

Accurately calculating the spring deflection load for an excavator is crucial for ensuring the safety and optimal performance of the machine. Overloading the spring can lead to permanent deformation or failure, which can result in costly repairs and potentially dangerous situations for operators and those around the machine.

4. Can the spring deflection load calculation be done manually or is specialized software needed?

The spring deflection load calculation for an excavator can be done manually using the formula F = kx, as long as the spring constant and distance of deflection are known. However, specialized software can also be used to assist in the calculation and provide more accurate results, especially for complex spring systems.

5. Are there any safety precautions to take when performing a spring deflection load calculation for an excavator?

It is important to always follow safety precautions when performing a spring deflection load calculation for an excavator. This includes using proper protective gear and ensuring the machine is safely secured and powered off before making any calculations or adjustments to the spring. If there are any doubts or concerns, it is best to consult a professional or the manufacturer for guidance.

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