- #1
P-Illiterate
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A .50 kg block sliding on horizontal frictionless surface is attached to one end of a horizontal spring (with k = 500 N/M) whose other end is fixed. The block has a kinetic energy of 20J as it pass through its equilibrium position (the point at which the spring force is zero.)
1.
I know this is wrong but
do I use K - 1/mv2
20 =.5*.50*v2
v -8.9 m/sI missed my lecture the day when his was taught, I don't have any idea how to solve any of this ... can you please help me??
- what is the speed of the block as it passes through its equilibrium position?
- at what rate is the spring doing work (power) as the block passes through the equilibrium pont?
- what is the maximum compression of the spring?
- at what rate is the spring doing work on the block as the block passes through a point 5 cm away from the sprig's equilibrium position and being stretched?
The Attempt at a Solution
1.
I know this is wrong but
do I use K - 1/mv2
20 =.5*.50*v2
v -8.9 m/sI missed my lecture the day when his was taught, I don't have any idea how to solve any of this ... can you please help me??