Springs, Masses, and Friction oh mY

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The discussion revolves around calculating the maximum amplitude of oscillation for a block resting on a frictionless table, attached to a spring, without slipping off. The spring constant (k = 150 N/m) and the coefficient of static friction (0.36) between the two blocks are provided. The force of friction must equal the spring force at maximum displacement to prevent slipping. Participants emphasize using the given values to find the frictional force and subsequently determine the amplitude. The thread highlights the importance of correctly applying the relevant equations to solve the problem.
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Homework Statement



A block with mass M = 5.5 kg rests on a frictionless table and is attached by a horizontal spring (k = 1.5E2 N/m) to a wall. A second block, of mass m = 1.32 kg, rests on top of M. The coefficient of static friction between the two blocks is 0.36. What is the maximum possible amplitude of oscillation such that m will not slip off M?

Homework Equations



F_spring=kx
F=ma
F_friction=(coeff friction)(normal force)=u*F_n

The Attempt at a Solution



So for the block to slide the force of friction must be equal too/less than the force imparted from the spring accelerating the blocks.
F_a=F_spring
Ma=u*m*g
a=#

The F_accel must equal the spring force at the peak (accel will be highest then)
F_a=F_spring=kx, where we can find the value of F_a, but we don't know the values of k or x.

I tried applying some engery type eqns like E=0.5kA^2 or E=KE+PE but we don't know any amplitudes, velocities, etc.

Help,
Brandon
 
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See, youre given k and youre given the coeff of friction and the masses. So you can find the frictional force. This must be equal to the spring force as you said (max displacement). From there you can find x, which is your amplitude.
 
chaoseverlasting said:
See, youre given k and youre given the coeff of friction and the masses. So you can find the frictional force. This must be equal to the spring force as you said (max displacement). From there you can find x, which is your amplitude.

Wow, forgot I was given "k". Don't have time now but will look at it later.

Thanks,
Brandon
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

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