- #1
mcfaker
- 43
- 0
Hi,
The standard enthalpy of formation of carbon gas or C(g) is the enthalpy change for the formation of 1 mole of carbon gas from its elements in their reference form which for carbon (I believe) is C(graphite).
Now I find the following standard enthalpy of formation for carbon gas / C(g) : 716.7 kJ
So now the formation reaction(or thermochemical equatation) is:
C(graphite) → C(g) ΔH= 716.7 kJ
Am I right? So if we add 716,7kJ to 1 mole of graphite ( note: not diamond) we will get carbon gas? Now carbon gas only excists at a temperature of 4827.0 °C so that means if we add 716.7 kJ it will increase the temperature up to 4827.0 °C?
Thanks in advance!
The standard enthalpy of formation of carbon gas or C(g) is the enthalpy change for the formation of 1 mole of carbon gas from its elements in their reference form which for carbon (I believe) is C(graphite).
Now I find the following standard enthalpy of formation for carbon gas / C(g) : 716.7 kJ
So now the formation reaction(or thermochemical equatation) is:
C(graphite) → C(g) ΔH= 716.7 kJ
Am I right? So if we add 716,7kJ to 1 mole of graphite ( note: not diamond) we will get carbon gas? Now carbon gas only excists at a temperature of 4827.0 °C so that means if we add 716.7 kJ it will increase the temperature up to 4827.0 °C?
Thanks in advance!