- #1
greypilgrim
- 548
- 38
Hi.
According to Wikipedia: The "one-way" speed of light, from a source to a detector, cannot be measured independently of a convention as to how to synchronize the clocks at the source and the detector.
Mid 20th century, the most precise measurements of the speed of light were done using cavity resonance. But how could standing waves form if the speeds were different for both ways, wouldn't either ##\lambda## or ##f## (or both) be different?
Also: Leaving the cavity away and just using a laser and a far away mirror, couldn't I just measure ##\lambda## for the leaving and reflected beam (e.g. with a diffraction grating) and ##f## (e.g. using the photoelectric effect) and if they both are the same, so must be ##c=\lambda\cdot f##?
According to Wikipedia: The "one-way" speed of light, from a source to a detector, cannot be measured independently of a convention as to how to synchronize the clocks at the source and the detector.
Mid 20th century, the most precise measurements of the speed of light were done using cavity resonance. But how could standing waves form if the speeds were different for both ways, wouldn't either ##\lambda## or ##f## (or both) be different?
Also: Leaving the cavity away and just using a laser and a far away mirror, couldn't I just measure ##\lambda## for the leaving and reflected beam (e.g. with a diffraction grating) and ##f## (e.g. using the photoelectric effect) and if they both are the same, so must be ##c=\lambda\cdot f##?