Star-Delta Circuit: Measuring Current with 6R Resistor

In summary, the conversation discusses the replacement of a 6R resistor with a galvanometer of the same internal resistance. The reading of the galvanometer will depend on the voltage or current source connected to the circuit. If a 1 A source is plugged in, the current through the 6R resistor is 1/34 R. The individual solved the problem by applying KVL and KCL equations.
  • #1
alanveron
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http://floti.bell.ac.uk/principles/star delta/img008.gif

sorry...i don't know how to post the pic here...juz want to know if 6R resistor is replaced by a galvanometer which has the internal resistance 6R,what will be the reading?
 
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  • #2
It depends on the voltage (current ) source connected to the circuit.

Let's say you plug a 1 A source to the entire circuit

I found out solving for the entire thing that the current trough the resistor of 6R is 1/34 R

I wrote KVL for each mini loop, and then wrote KCL at the top, at the bottom and in b). then solved for each current.
 
  • #3


If a galvanometer with an internal resistance of 6R is used instead of the 6R resistor in the Star-Delta circuit, the reading will depend on the current flowing through the circuit. The galvanometer will act as a load and will affect the overall resistance of the circuit. Therefore, the reading on the galvanometer may not accurately represent the actual current in the circuit. It is important to use the correct components in a circuit to ensure accurate measurements.
 
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