State the domain of the function and the domain of its derivative

Yes, that is correct!3rd one i know its the quotient rule but not sure where to go with this one USE the quotient rule of course! What is (x2+ 1)' ? What is (x- 2)'? Do it just like you did number 2.The derivative of (x^2 + 1) is 2x, and the derivative of (x - 2) is 1. So, using the quotient rule, the derivative of
  • #1
bballj228
5
0
Find the derivative. State the domain of the function and the domain of its derivative.

f(x) = x + √x

f(x) = (3 + x) / 1-3x

Find F'(a)

f(x) = (x^2 + 1) / (x - 2)

f(x) = √3x + 1
 
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  • #2
And your work so far...?
 
  • #3


For the first one i got up to x + √x = x^1/2 = x^3/2

2nd one 1(1-3x) - (-3)(3 + x) all over (1-3x)^2 = 10 / (1 - 3x) ^2

3rd one i know its the quotient rule but not sure where to go with this one

For the fourth i tried the chain rule

√3x + 1 = 3x^1/2 + 1 = 1/2(3x)^1/2
 
  • #4


bballj228 said:
For the first one i got up to x + √x = x^1/2 = x^3/2
? No, [itex]x+ \sqrt{x}[/itex] is NOT equal to [itex]x^{1/2}= \sqrt{x}[/itex] and NEITHER of those is equal to [itex]x^{1/2}[/itex]. Did you mean that [itex]\sqrt{x}= x^{1/2}[/itex]? And that the derivative is [itex]x^{3/2}[/itex]? That last is not correct, either. Surely, you know what the derivative of x= x1 is 1? And what is the derivative of [itex]\sqrt{x}= x^{1/2}[/itex]?

2nd one 1(1-3x) - (-3)(3 + x) all over (1-3x)^2 = 10 / (1 - 3x) ^2
Yes, that is correct!

3rd one i know its the quotient rule but not sure where to go with this one
USE the quotient rule of course! What is (x2+ 1)' ? What is (x- 2)'? Do it just like you did number 2.

For the fourth i tried the chain rule

√3x + 1 = 3x^1/2 + 1 = 1/2(3x)^1/2

Is that √(3)x+ 1, √(3x)+ 1, or √(3x+1)? In any case, none if those is equal to 3x^(1/2)+ 1.

The derivative of √(3) x+ 1 should be trivial. √(3x)+ 1 can be done as √(3)x^(1/2)+ 1, and √(3x+1) should be done using the chain rule: √(3x+1)= √u with u= 3x+1:
(√(3x+1))'= (du^(1/2)/du)(d(3x+1)/dx).
 
  • #5


HallsofIvy said:
? No, [itex]x+ \sqrt{x}[/itex] is NOT equal to [itex]x^{1/2}= \sqrt{x}[/itex] and NEITHER of those is equal to [itex]x^{1/2}[/itex]. Did you mean that [itex]\sqrt{x}= x^{1/2}[/itex]? And that the derivative is [itex]x^{3/2}[/itex]? That last is not correct, either. Surely, you know what the derivative of x= x1 is 1? And what is the derivative of [itex]\sqrt{x}= x^{1/2}[/itex]?

No, I don't know actually.
 
  • #6


Use the power rule for differentiation. What is the derivative of x^n? Just apply it to x^1/2.
 

FAQ: State the domain of the function and the domain of its derivative

What is the domain of a function?

The domain of a function is the set of all possible input values or independent variables for which the function is defined. In other words, it is the set of all values that can be plugged into the function to produce a valid output.

How is the domain of a function represented?

The domain of a function is typically represented using interval notation or set notation. For example, if the function is defined for all real numbers, the domain can be represented as (-∞, ∞) or {x|x ∈ ℝ}.

Can the domain of a function be restricted?

Yes, the domain of a function can be restricted based on the context or purpose of the function. For example, the domain of a square root function can be restricted to non-negative real numbers to ensure a real output.

What is the domain of the derivative of a function?

The domain of the derivative of a function is the same as the domain of the original function. Both the function and its derivative are defined for the same set of input values.

How is the domain of the derivative related to the domain of the function?

The domain of the derivative is a subset of the domain of the function. This means that the derivative is only defined for a subset of the input values that the function is defined for. However, the domain of the derivative can also be restricted if the function has any discontinuities or undefined points within its domain.

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