Static equilibrium (conceptual)

AI Thread Summary
For an object to be in static equilibrium, the net force and net torque must both be zero. There is confusion regarding whether the object's velocity must also be zero, as some sources suggest that an object can have a constant velocity without acceleration, thus still fulfilling the conditions for equilibrium. However, class materials often imply that static equilibrium requires the object to be at rest. The discussion highlights conflicting interpretations from various educational resources, leading to uncertainty about the definition of static equilibrium. Ultimately, clarity on whether an object in static equilibrium must be at rest remains a point of contention.
kermitthefrog
Messages
3
Reaction score
0
In order for an object to be in static equilibrium

a)the net force in all directions must be zero
b)the net torque must be zero
c) the object's velocity must be zero
d) a and b are correct
e) all of the above


2. I know that the net force in all directions must be equal to zero, also teh sum of the net torque must be equal to zero. I am confusted about the object's velocity being zero.

3. An object can have non-zero velocity and not be accelerating(ie it has a constant velocity), which would fulfill the idea that no net force is acting upon it. However in my class text, it keeps stating that the object is at rest. I'm not sure if this is just a specific example of equilibrium, or if all objects in equilibrium must be at rest (ie velocity= 0). From the searches that I have done I can't tell if the object's velocity must be zero...any explanations?



3.attempt at solution, because I think you can have constant velocity in which you are not accelerating, I believe the answer is D, both choice A and B are correct.
 
Physics news on Phys.org
It's a good question, and boils down to whether the object must be at rest or not.

A quick google search gives conflicting answers. Wolfram claims that zero net force and torque are sufficient for static equilibrium, whereas wikipedia and physicsclassroom.com claim the object must be at rest as well. You can look at these three links, and hopefully decide which is most consistent with your class's use of static equilibrium:

http://en.wikipedia.org/wiki/Static_equilibrium
http://scienceworld.wolfram.com/physics/StaticEquilibrium.html
http://www.physicsclassroom.com/class/vectors/U3l3c.cfm
 
I multiplied the values first without the error limit. Got 19.38. rounded it off to 2 significant figures since the given data has 2 significant figures. So = 19. For error I used the above formula. It comes out about 1.48. Now my question is. Should I write the answer as 19±1.5 (rounding 1.48 to 2 significant figures) OR should I write it as 19±1. So in short, should the error have same number of significant figures as the mean value or should it have the same number of decimal places as...
Thread 'Minimum mass of a block'
Here we know that if block B is going to move up or just be at the verge of moving up ##Mg \sin \theta ## will act downwards and maximum static friction will act downwards ## \mu Mg \cos \theta ## Now what im confused by is how will we know " how quickly" block B reaches its maximum static friction value without any numbers, the suggested solution says that when block A is at its maximum extension, then block B will start to move up but with a certain set of values couldn't block A reach...
Thread 'Calculation of Tensile Forces in Piston-Type Water-Lifting Devices at Elevated Locations'
Figure 1 Overall Structure Diagram Figure 2: Top view of the piston when it is cylindrical A circular opening is created at a height of 5 meters above the water surface. Inside this opening is a sleeve-type piston with a cross-sectional area of 1 square meter. The piston is pulled to the right at a constant speed. The pulling force is(Figure 2): F = ρshg = 1000 × 1 × 5 × 10 = 50,000 N. Figure 3: Modifying the structure to incorporate a fixed internal piston When I modify the piston...
Back
Top