goonking said:Homework Statement
Homework Equations
Fs = μ FN
The Attempt at a Solution
Ok, so I drew a free body diagram and tilted it 90 degrees so that Fg of the small box points right and Fstatic points left.
Fg = 4.7 kg x 9.8m/s2 = 46 N
we want Fs to equal 46 N , correct? so we use the formula
Fs = (0.71) x FN
FN being the force of big box on small box
.71 x FN = 46 N
FN = 64.8N
Which is wrong. any help?
oh, silly me.ehild said:
Correct!goonking said:
Static friction is a force that prevents two surfaces from sliding past each other when they are in contact and not moving relative to each other. In the case of a sliding box on a plane, static friction acts in the opposite direction of the applied force, preventing the box from sliding down the plane.
The coefficient of static friction is determined by dividing the maximum amount of static friction by the applied force. This value is dependent on the materials of the surfaces in contact and the roughness of those surfaces.
The static friction of a sliding box on a plane can be affected by the weight of the box, the angle of the plane, the coefficient of static friction between the surfaces, and the roughness of the surfaces in contact.
The angle of the plane affects the component of the weight of the box that acts in the direction of the plane, which in turn affects the maximum amount of static friction that can be exerted on the box. As the angle of the plane increases, the component of the weight acting in the direction of the plane decreases, resulting in a decrease in the maximum static friction.
Static friction prevents two surfaces from sliding past each other when they are not moving relative to each other, while kinetic friction acts on two surfaces that are moving relative to each other. In the case of a sliding box on a plane, static friction is present when the box is not moving, but once it starts moving, the force of kinetic friction takes over.