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kimann020
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Homework Statement
Determine allowable load on steel tube
L= 14 in
A= 11 in ^2
Es= 30 x10^6
θ=24,000 psi
δ= .008
Homework Equations
δ=PL/EA
θ=P/A
The Attempt at a Solution
.008=P(14 in)/(30 x 10^6)(11 in)^2
P=188571.4 lb
θ=P/A
24,000 psi=P/11 in^2
P=264,000?
My teach is telling me that the answer is P=2181.8 lbs i don't understand how or what i did wrong