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Chandasouk
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Calculate the resultant force’s magnitude and the couple moment.
Let a = 3.70 m
w1=5.35kN/m
w2=4.00kN/m
The resultant force of the triangle is 1/2(3.70)(5.35)=9.898 kN
The resultant force of the rectangle is (4)(3.70) = 14.8kN
So FR (The force's magnitude) is 24.69kN
I found the location of the triangle's load to be 1/3(3.7) = 1.233m
I found the location of the rectangles load to be 1/2(3.70)+3.7 = 5.550m
So I calculated the couple moment MRa (Taking counter clockwise to be POSITIVE) I get
(9.898)(1.233)+(14.8)(5.55) = 94.3kN*m
but when I put these answers down for MasteringEngineering, they are incorrect. Where did I go wrong?
Calculate the resultant force’s magnitude and the couple moment.
Let a = 3.70 m
w1=5.35kN/m
w2=4.00kN/m
The resultant force of the triangle is 1/2(3.70)(5.35)=9.898 kN
The resultant force of the rectangle is (4)(3.70) = 14.8kN
So FR (The force's magnitude) is 24.69kN
I found the location of the triangle's load to be 1/3(3.7) = 1.233m
I found the location of the rectangles load to be 1/2(3.70)+3.7 = 5.550m
So I calculated the couple moment MRa (Taking counter clockwise to be POSITIVE) I get
(9.898)(1.233)+(14.8)(5.55) = 94.3kN*m
but when I put these answers down for MasteringEngineering, they are incorrect. Where did I go wrong?
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