- #1
WrongMan
- 149
- 15
hello everyone. i need help understanding this statement:
d(lnΩ)/dE = 1/kbT
so Ω are the posible microstates for energy E, and the derivative of Ω w.r.t E is 1/kbT.
why?
what i understand so far is: looking at the division of energy of two "connected" systems the energy will divide itself in a way that maximizes the total possible microstates, and since the total number of microstates is: Ω1(E1)*Ω2(E2)
(where "Ω1(E1)" means posible microstates at E1 for system 1) this would mean:
Et=E1+E2 and
Ωt(Et)=Ω1(E1)*Ω2(E2)
and since i want to maximize this i say:
dΩt/dEt=0
so now what? i feel that I am close but i can't get there
d(lnΩ)/dE = 1/kbT
so Ω are the posible microstates for energy E, and the derivative of Ω w.r.t E is 1/kbT.
why?
what i understand so far is: looking at the division of energy of two "connected" systems the energy will divide itself in a way that maximizes the total possible microstates, and since the total number of microstates is: Ω1(E1)*Ω2(E2)
(where "Ω1(E1)" means posible microstates at E1 for system 1) this would mean:
Et=E1+E2 and
Ωt(Et)=Ω1(E1)*Ω2(E2)
and since i want to maximize this i say:
dΩt/dEt=0
so now what? i feel that I am close but i can't get there
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