Stats: Joint Density/Independence - Method of transformation (please check)

In summary, joint density refers to the probability distribution of two or more random variables, while independence means that the values of one variable do not affect the values of another. Joint density and independence are related because if two variables are independent, their joint density can be represented as the product of their individual probability distributions. The method of transformation in statistics is used to transform data into a different form for analysis, such as logarithmic or exponential transformations. In joint density, this method is used to transform related variables into independent ones, which can then be represented as the product of their individual probability distributions. Using this method can simplify data, identify relationships between variables, and allow for easier mathematical operations, potentially leading to more accurate models and predictions. However, there
  • #1
Ted123
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Homework Statement



Let [itex]X_1[/itex] and [itex]X_2[/itex] be independent [itex]\text{Exp}(\lambda)[/itex] random variables.

(i) Find the joint density of [itex]Y_1 = X_1 + X_2[/itex] and [itex]\displaystyle Y_2 = \frac{X_1}{X_2}[/itex]
(ii) Show that [itex]Y_1[/itex] and [itex]Y_2[/itex] are independent.

The Attempt at a Solution



(i) By independence of [itex]X_1[/itex] and [itex]X_2[/itex]

[itex]\begin{displaymath} f_{X_1,X_2} (x_1,x_2) = f_{X_1} (x_1) f_{X_2} (x_2) = \left\{ \begin{array}{lr}
\lambda ^2 e^{-\lambda (x_1 + x_2)} & : (x_1,x_2) \in S \\
0 & : \text{o/w}\;\;\;\;\;\;\;\;\;\;\;\,
\end{array}
\right.
\end{displaymath}[/itex]

where [itex]S=[0,\infty )\times [0,\infty )[/itex]

[itex]y_1 = x_1 +x_2[/itex]

[itex]\displaystyle y_2 = \frac{x_1}{x_2}[/itex]

Inverting the transformation

[itex]\displaystyle x_1 = \frac{y_1 y_2}{y_2 +1}[/itex]

[itex]\displaystyle x_2 = \frac{y_1}{y_2 +1}[/itex]

for [itex](y_1 , y_2)\in T[/itex] where [itex]T=[0,\infty )\times [0,\infty )[/itex]

[itex]J=\begin{vmatrix} \displaystyle \frac{\partial x_1}{\partial y_1} & \displaystyle \frac{\partial x_1}{\partial y_2} \\ \displaystyle \frac{\partial x_2}{\partial y_1} & \displaystyle \frac{\partial x_2}{\partial y_2} \end{vmatrix}[/itex]

[itex]J=\begin{vmatrix} \displaystyle \frac{y_2}{y_2 +1} & \displaystyle \left(\frac{y_1}{y_2 +1}-\frac{y_1 y_2}{(y_2 +1)^2} \right) \\ \displaystyle\frac{1}{y_2 +1} & \displaystyle -\frac{y_1}{(y_2 +1)^2} \end{vmatrix} = \displaystyle -\frac{y_1}{(y_2 +1)^2}[/itex]

[itex]\begin{displaymath} f_{Y_1,Y_2} (y_1,y_2) = \left\{ \begin{array}{lr}
\displaystyle f_{X_1,X_2} \left(\frac{y_1 y_2}{y_2 +1} , \frac{y_1}{y_2 +1}\right) |J| & : (x_1,x_2) \in T \\
0 & : \text{o/w}\;\;\;\;\;\;\;\;\;\;\;\;
\end{array}
\right.
\end{displaymath}[/itex]

[itex]\begin{displaymath} f_{Y_1,Y_2} (y_1,y_2) = \left\{ \begin{array}{lr}
\displaystyle \lambda ^2 e^{-\lambda y_1} \frac{y_1}{(y_2 +1)^2} & : (x_1,x_2) \in T \\
0 & : \text{o/w}\;\;\;\;\;\;\;\;\;\;\;\;
\end{array}
\right.
\end{displaymath}[/itex]

(ii) To determine independence, calculate marginals.

[itex]\begin{displaymath} f_{Y_1} (y_1) = \left\{ \begin{array}{lr}
\displaystyle y_1 \lambda ^2 e^{-\lambda y_1} \int^{\infty}_0 \frac{1}{(y_2 +1)^2}\;dy_2 & : y_1 \geq 0 \\
0 & : \text{o/w}\;\;\;\,
\end{array}
\right.
\end{displaymath}[/itex]

[itex]\begin{displaymath} f_{Y_1} (y_1) = \left\{ \begin{array}{lr}
\displaystyle y_1\lambda ^2 e^{-\lambda y_1} & : y_1 \geq 0 \\
0 & : \text{o/w}\;\;\;\,
\end{array}
\right.
\end{displaymath}[/itex]

[itex]\begin{displaymath} f_{Y_2} (y_2) = \left\{ \begin{array}{lr}
\displaystyle \frac{\lambda ^2}{(y_2 +1)^2} \int^{\infty}_0 y_1 e^{-\lambda y_1} \;dy_1 & : y_2 \geq 0 \\
0 & : \text{o/w}\;\;\;\,
\end{array}
\right.
\end{displaymath}[/itex]

[itex]\begin{displaymath} f_{Y_2} (y_2) = \left\{ \begin{array}{lr}
\displaystyle \frac{1}{(y_2 +1)^2} & : y_2 \geq 0 \\
0 & : \text{o/w}\;\;\;\,
\end{array}
\right.
\end{displaymath}[/itex]

[itex]\therefore[/itex] since [itex]f_{Y_1,Y_2} (y_1,y_2) = f_{Y_1} (y_1) f_{Y_2} (y_2), Y_1[/itex] and [itex]Y_2[/itex] are independent.
 
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  • #2


Thank you for your detailed attempt at solving this problem. However, I would like to point out a couple of mistakes and suggest some improvements.

Firstly, in part (i) when you calculate the joint density of Y_1 and Y_2, you forgot to include the absolute value of the Jacobian in the formula. It should be:

\begin{displaymath} f_{Y_1,Y_2} (y_1,y_2) = \left\{ \begin{array}{lr}
\displaystyle f_{X_1,X_2} \left(\frac{y_1 y_2}{y_2 +1} , \frac{y_1}{y_2 +1}\right) \left|\frac{\partial(x_1,x_2)}{\partial(y_1,y_2)}\right| & : (x_1,x_2) \in T \\
0 & : \text{o/w}\;\;\;\;\;\;\;\;\;\;\;\;
\end{array}
\right.
\end{displaymath}

Additionally, in the calculation of the Jacobian, there is a small error in the second row, first column. It should be $\frac{y_1}{(y_2+1)^2}$ instead of $\frac{1}{y_2+1}$.

Secondly, in part (ii) when you calculate the marginal densities of Y_1 and Y_2, you made a mistake in the limits of integration. The integral should be from 0 to $\infty$ for both cases, not from 0 to 1.

Lastly, I would suggest using a more organized and clear structure for your solution. For example, you can start by stating the given information and then clearly defining the transformations for Y_1 and Y_2. Then, you can calculate the Jacobian and use it to find the joint density of Y_1 and Y_2. Finally, you can calculate the marginals and show that they are indeed independent. This will make your solution easier to follow and understand.

Overall, great effort in attempting to solve this problem. Keep up the good work!
 

FAQ: Stats: Joint Density/Independence - Method of transformation (please check)

What is joint density and how is it related to independence?

Joint density refers to the probability distribution of two or more random variables. Independence means that the values of one variable do not affect the values of another variable. Joint density and independence are related because if two variables are independent, their joint density can be represented as the product of their individual probability distributions.

What is the method of transformation in statistics?

The method of transformation in statistics refers to a technique used to transform a set of data into a different form. This is often used to simplify data or make it more suitable for analysis. Examples of transformation methods include logarithmic, exponential, and power transformations.

How is the method of transformation used in joint density?

In joint density, the method of transformation is used to transform a set of related variables into a new set of variables that are independent of each other. This is done by applying a transformation function to the original variables. The resulting joint density of the transformed variables can then be represented as the product of their individual probability distributions.

What are the benefits of using the method of transformation in joint density?

The method of transformation in joint density allows for the simplification of data and the identification of relationships between variables. It also enables the use of easier mathematical operations and can make it easier to interpret the data. Additionally, using transformation can sometimes lead to more accurate statistical models and predictions.

Are there any limitations or considerations to keep in mind when using the method of transformation in joint density?

Yes, there are a few limitations and considerations to keep in mind when using the method of transformation in joint density. First, the transformation function must be carefully chosen and may not always be applicable to all types of data. Additionally, the transformed variables may not always have a simple interpretation, making it more challenging to explain the results. It is also important to consider the potential impact of outliers on the transformation process.

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