Stefan-Boltzmann's Law. How to apply to the Sun

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In summary, Stefan-Boltzmann's Law states that the total energy radiated per unit surface area of a black body is proportional to the fourth power of its absolute temperature. To apply this law to the Sun, one can calculate the Sun's luminosity by using its surface temperature (approximately 5778 K) and its radius. By substituting these values into the formula, one can determine the Sun’s total energy output, illustrating the relationship between temperature and energy radiation in stellar bodies.
  • #1
PMNIMG
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Homework Statement
Use the Stefan-Boltzmann's Law and calculate Sun's radius.
T☉=5772K
L☉= 3.828×10^(26) W
Relevant Equations
E=σT^4
L=4πr^2*σT^4
r=(L/4π*σT^4)^(1/2)
r^2=(3.828*10^(26))/(4π*σ(5772)^4)
It's diffrent from what I know...
 
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  • #2
PMNIMG said:
Homework Statement: Use the Stefan-Boltzmann's Law and calculate Sun's radius.
T☉=5772K
L☉= 3.828×10^(26) W
Relevant Equations: E=σT^4
L=4πr^2*σT^4
r=(L/4π*σT^4)^(1/2)

r=(3.828*10^(26))/(4π*σ(5772)^4)
It's diffrent from what I know...
Did you mean ##r^2=…##?
Other than that, what is stopping you?
 
  • #3
haruspex said:
Did you mean ##r^2=…##?
Other than that, what is stopping you?
Oh, sorry. I modified it now.
From what I know, the radius of the sun is 696340000m. It is diffrent from the solution...
And I don't know what seems to be the problem.
 
  • #4
According to NASA, the suns diameter is 695,700,000 meters, which according to your maths is accurate to 4 decimal places. So I also don't know what the problem is, as there doesn't appear to be one. Even the number you display as the given radius is off by less than 1/10 of 1 percent.
 
  • #5
can you show me how to calculate?
I think it's diffrent from mine...
 
  • #6
PMNIMG said:
can you show me how to calculate?
I think it's diffrent from mine...
@OmCheeto did not (I think) do any calculation other than to find the % difference.
Your result agrees pretty well with NASA's. What is the given solution?
 
  • #7
Oh, I think I miscalculated...
sorry I disturbed you all with dumb question...
I think I put km instead of m...
 
  • #8
PMNIMG said:
Oh, I think I miscalculated...
sorry I disturbed you all with dumb question...
I think I put km instead of m...
No problem.
 
  • #9
I do that sometimes...
If you can't find anything odd about my qusetion, please tell me reason!
sorry
 

FAQ: Stefan-Boltzmann's Law. How to apply to the Sun

What is Stefan-Boltzmann's Law?

Stefan-Boltzmann's Law states that the total energy radiated per unit surface area of a black body is directly proportional to the fourth power of its absolute temperature. Mathematically, it is expressed as \( E = \sigma T^4 \), where \( E \) is the emissive power, \( \sigma \) is the Stefan-Boltzmann constant, and \( T \) is the absolute temperature in Kelvin.

How can Stefan-Boltzmann's Law be applied to the Sun?

Stefan-Boltzmann's Law can be applied to the Sun by treating it as an approximate black body. By knowing the Sun's surface temperature (around 5778 K) and using the Stefan-Boltzmann constant, we can calculate the total energy output per unit area of the Sun's surface. This helps in determining the Sun's luminosity, which is the total energy radiated by the Sun per second.

What is the Stefan-Boltzmann constant?

The Stefan-Boltzmann constant (\( \sigma \)) is a physical constant denoted by \( \sigma \) and has a value of approximately \( 5.67 \times 10^{-8} \) W/m²K⁴. It is used in the Stefan-Boltzmann Law to relate the temperature of a black body to the total energy it radiates.

How do you calculate the Sun's luminosity using Stefan-Boltzmann's Law?

To calculate the Sun's luminosity, you first determine the energy radiated per unit area using \( E = \sigma T^4 \), where \( T \) is the Sun's surface temperature. Then, multiply this energy by the Sun's surface area \( 4\pi R^2 \), where \( R \) is the Sun's radius. The resulting product gives the Sun's luminosity \( L = 4\pi R^2 \sigma T^4 \).

Why is the Sun considered an approximate black body in the context of Stefan-Boltzmann's Law?

The Sun is considered an approximate black body because it emits a spectrum of radiation that closely follows the black body radiation curve. Although the Sun is not a perfect black body, it emits radiation across a wide range of wavelengths, and its emission can be reasonably approximated using black body radiation principles, allowing us to apply Stefan-Boltzmann's Law to estimate its energy output.

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