MHB Stephanie's question at Yahoo Answers (Domain question)

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The function f(x) = 1 / (4 / ((x-1) - 2)) simplifies to f(x) = (x-1) / (6-2x) for x ≠ 1. The function is undefined at x = 1 and x = 3, leading to the domain being all real numbers except these two values. To find the value of 1 in the context of the function, it is important to understand the restrictions on x that affect the function's definition. This mathematical explanation clarifies how to approach similar domain questions. The discussion emphasizes the importance of identifying points where the function is undefined.
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Here is the question:

f(x) = (1) / (4 / ((x-1) - 2))

I got the 3 but I can not get the 1.

Can you possibly tell me what this would be called so I can google it, and if possible explain mathematically how to get the 1; besides substituting in numbers?

Here is a link to the question:

Math Help - Domain Question? - Yahoo! Answers

I have posted a link there to this topic, so the OP can find my response.
 
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Re: Stepanie's question at Yahoo! Answers (Domain question)

Hello Stephanie,

The funcion is $f(x)=\dfrac{1}{\dfrac{4}{x-1}-2}$. But $\dfrac{4}{x-1}$ is defined if and only if $x\neq 1$ so, $$f(x)=\dfrac{1}{\dfrac{4-2x+2}{x-1}}=\dfrac{x-1}{6-2x}\quad (\mbox{if }x\neq 1)$$ For $x\neq 1$, $f(x)$ is defined if and only if $x\neq 3$. Hence, $\mbox{Dom } f=\mathbb{R}-\{1,3\}$
 
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