- #1
karush
Gold Member
MHB
- 3,269
- 5
$$\displaystyle
\int\frac{{x}^{2}}{\left(4-{x}^{2}\right)^{3/2}} \ dx$$
$u=4-{x}^{2} \ \ \ du=-2x dx \ \ \ x=\sqrt{4-u}$
$$\displaystyle
\int\frac{4-u}{
\left(u\right)^{3/2}} -2 \sqrt{4-u}\ du$$
Stuck
\int\frac{{x}^{2}}{\left(4-{x}^{2}\right)^{3/2}} \ dx$$
$u=4-{x}^{2} \ \ \ du=-2x dx \ \ \ x=\sqrt{4-u}$
$$\displaystyle
\int\frac{4-u}{
\left(u\right)^{3/2}} -2 \sqrt{4-u}\ du$$
Stuck