- #1
BOAS
- 553
- 19
Homework Statement
For [itex]\mathbf{F} = y \mathbf{i} - x \mathbf{j} + 4z \mathbf{k}[/itex] evaluate the surface integral of [itex](\nabla \times \mathbf{F}) · k[/itex] over the 2D surface of the disc [itex]x^{2} + y^{2} \leq 4, z = \frac{H}{2}[/itex]
Homework Equations
The Attempt at a Solution
I am unsure of my answer to this question for a few reasons.
1. Does it make sense for my answer to be negative? I thought we usually choose the unit vector such that the answer comes out to be positive, but it was chosen for me here.
2. Is the 'z' information only relevant to performing the closed loop integral?
My working:
[itex]\nabla \times \mathbf{F} = -2 \mathbf{k}[/itex]
[itex](\nabla \times \mathbf{F}) · k = -2[/itex]
[itex]\int_{s}(\nabla \times \mathbf{F}) · k = \int^{2\pi}_{0} \int^{4}_{0} -2 \rho d\rho d\phi[/itex]
[itex]\int_{s}(\nabla \times \mathbf{F}) · k = (\int^{4}_{0} -2 \rho d\rho)(\int^{2\pi}_{0} d\phi)[/itex]
[itex]\int_{s}(\nabla \times \mathbf{F}) · k = [-\rho^{2}]^{4}_{0} [\phi]^{2\pi}_{0} = -32\pi[/itex]
Also, should it be [itex](-\rho)^2[/itex] or [itex]-(\rho^2)[/itex]? The former would solve my problem of having a negative answer, but I'm not sure...
Thanks!