- #1
lpettigrew
- 115
- 10
- Homework Statement
- Using labelled axes, draw stress-strain graphs for;
1.Rubber
2.Copper
3.Glass
4.Mild Steel
On the sketch graph for copper mark the following points: a - the limit of proportionality, b- the
elastic limit, c - the yield stress, d - the ultimate tensile stress, e - the breaking point
- Relevant Equations
- S
Hello, so I am not actually seeking help sketching the stress strain graphs. However, I am rather confused about the last part of the question to comprehensively label the stress-strain graph of copper with the limit of proportionality etc.
Evaluating the graph, it becomes clear that these points are not directly discernible, at least not to the degree of detail specified by he question. Do you think that this is a mistake and that the question meant to ask one to identify these points on the graph for mild steel?
I have just attached two images from online showing an average stress-strain graph for copper and mild-steel to support my thoughts.
Also, I have not sketched them out yet but I have also attached what I think a stress-strain graph for;
1. Rubber looks like. This forms a hysteresis loop.
2. Glass looks like. Materials lacking in mobility like glass are usually brittle rather than ductile. Brittle materials do not have a well-defined yield point, therefore, the ultimate strength and breaking strength are the same. Glass would not usually show any plastic deformation but fail while the deformation is elastic. Thus, an average stress–strain curve for a brittle material will be linear.
Evaluating the graph, it becomes clear that these points are not directly discernible, at least not to the degree of detail specified by he question. Do you think that this is a mistake and that the question meant to ask one to identify these points on the graph for mild steel?
I have just attached two images from online showing an average stress-strain graph for copper and mild-steel to support my thoughts.
Also, I have not sketched them out yet but I have also attached what I think a stress-strain graph for;
1. Rubber looks like. This forms a hysteresis loop.
2. Glass looks like. Materials lacking in mobility like glass are usually brittle rather than ductile. Brittle materials do not have a well-defined yield point, therefore, the ultimate strength and breaking strength are the same. Glass would not usually show any plastic deformation but fail while the deformation is elastic. Thus, an average stress–strain curve for a brittle material will be linear.