String gets deformed and released - derive equation

In summary, the conversation discusses finding the analytical solution for a graph showing an infinite string on the x-axis with a deformed middle part. The problem involves finding the displacement of the string for t>0 and sketching the string displacement and characteristics diagram for different times. The solution involves taking the derivative of the graph and using d'Alembert's solution to the wave equation, with the initial condition of zero velocity due to the string being "released". The conversation also mentions the use of the chain rule and Dirac delta in expressing the derivative.
  • #1
snickersnee
34
0

Homework Statement


[/B]
This graph shows an infinite string on the x-axis. The middle part is deformed as shown. The string is released at time t=0
- give the analytical solution of the problem, i.e. find
upload_2015-9-7_14-51-42.png
for t>0
- sketch the string displacement \xi(x) for a sequence of times t. (I'd like to know what some good times would be, but I guess that would be clear once I get the equation.
- sketch the characteristics diagram (x,t diagram) for the problem. (I know I could just plug in points to the equation, but is there an organized way to do this?)


upload_2015-9-7_14-43-14.png

Homework Equations



(see part 3)[/B]

The Attempt at a Solution


I know the graph above is expressed as follows:
tex?%5CLARGE%20%5Cxi%28x%2C0%29%3D%5Csin%7Bx%7D%20%5Ccdot%20rect%7B%5Cfrac%7Bx%7D%7B2%5Cpi%7D%7D.gif

I need to get the derivative of this in order to find
upload_2015-9-7_14-56-41.png
it looks like it'll be the chain rule with cosine as the derivative of sine, and the derivative of the rect will be impulses at -pi and +pi, but how do I express that mathematically? I think it's Dirac delta or something, but could someone please remind me how to write it? It's been a while since I had to do this.
On the other hand, there are no t's in the equation so does this mean the derivative would be 0?
 
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  • #2
The fact that they say that the string is "released" indicates that the initial condition on the velocity is zero. Once you know this, you can simply apply d'Alembert's solution to the wave equation and you are done.
 
  • #3
Orodruin said:
The fact that they say that the string is "released" indicates that the initial condition on the velocity is zero. Once you know this, you can simply apply d'Alembert's solution to the wave equation and you are done.

Thanks for your response. But I have to graph it too, what would be some good times to plug in? And how do I make the characteristics diagram?
 

FAQ: String gets deformed and released - derive equation

What is the equation for the deformation of a string when released?

The equation for the deformation of a string when released is F = kx, where F is the force applied to the string, k is the spring constant, and x is the displacement of the string from its equilibrium position.

What is the significance of the spring constant in the deformation of a string?

The spring constant, k, is a measure of the stiffness of the string. A higher spring constant indicates a stiffer string that requires more force to deform it, while a lower spring constant indicates a more flexible string that can be easily deformed.

Can the deformation equation be applied to all types of strings?

Yes, the deformation equation F = kx can be applied to all types of strings, regardless of their material or shape. However, the spring constant may vary depending on the properties of the string.

How does the length of the string affect its deformation?

According to Hooke's law, the deformation of a string is directly proportional to its length. This means that a longer string will experience a greater displacement when the same force is applied compared to a shorter string with the same spring constant.

What other factors can affect the deformation of a string?

Aside from the force applied and the spring constant, the diameter and material of the string can also affect its deformation. Thicker strings and those made of stiffer materials will have a higher spring constant and thus require more force to deform.

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