String rotating to make a cone, find period and tension

[s3a]

Homework Statement

"A mass m = 16.0 kg is attached to the lower end of a massless string of length L = 71.0 cm. The upper
end of the string is held fixed. Suppose that the mass moves in a circle at constant speed, and that the
string makes an angle theta = 25deg with the vertical, as shown in the figure."
(See attachment on page 2)

Homework Equations

T = 2pi*r/v

The Attempt at a Solution

I found tension = (16)(9.8)/(cos25deg) (not sure if this is the correct answer though but I think it is)

T = 2pi*r/v I found radius = 0.71m * (sin25deg)
but I need to find velocity I'm guessing so that I can get period T.

Any help would be greatly appreciated!
Thanks in advance!

 

[anathema]

Thank you for your post. I would like to offer some guidance on how to approach this problem.

Firstly, it is important to carefully read and understand the given information. From the information provided, we can see that a mass of 16.0 kg is attached to a string of length 71.0 cm, and that the mass moves in a circle at constant speed while the string makes an angle of 25 degrees with the vertical. This forms a right triangle, where the hypotenuse is the length of the string and the adjacent side is the radius of the circle.

Next, we can use the given equation T = 2pi*r/v to find the tension in the string. However, to do so, we need to first find the velocity of the mass. To find the velocity, we can use the fact that the mass moves at a constant speed in a circle, which means that its centripetal acceleration is constant. We can use the equation a = v^2/r to find the velocity, where a is the centripetal acceleration and r is the radius of the circle.

Once we have found the velocity, we can substitute it into the equation for tension to find the value of T. From there, we can use the equation for period T = 2pi*r/v to find the period of the motion.

I hope this helps. Good luck with your problem!