- #1
binbagsss
- 1,265
- 11
Homework Statement
Attached
Homework Equations
The Attempt at a Solution
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where ##\tau## and ##\sigma## are world-sheet parameters.
where ##h_{ab}## is the world-sheet metric.
To be honest, I am trying to do analogous to general relativity transformations, since this is new to me, so in that case an tensor with two lower indicies transforms as:
## h'_{ab}=h_{cd}\Lambda^{c}_{a}\Lambda^{d}_{b}##
So, to write it all out to make sure I understand clearly...
##h'_{11}=h_{cd}\Lambda^{c}_{1}\Lambda^{d}_{1}=h_{11}\Lambda^{1}_{1}\Lambda^{1}_{1} +h_{22}\Lambda^{2}_{1}\Lambda^{2}_{1} ##
and
##h'_{22}=h_{cd}\Lambda^{c}_{2}\Lambda^{d}_{2}=h_{11}\Lambda^{1}_{2}\Lambda^{1}_{2} + h_{22}\Lambda^{2}_{2}\Lambda^{2}_{2} ##
And, since ##h_{ab}## is the metric on the world-sheet is a funciton of ##\tau## and ##\sigma##, let ##X^{u}=(\tau,\sigma)## , then were ##\Lambda^{u}_{v}=\frac{\partial x^{u}}{\partial x'_v}##
(Apologies the convention I believe is to denote the above with ##\Lambda^{-1 u}_v ##)
So here ## X'^{u}= (\tau',\sigma')=(\tau^2/2,1)##
So then ##\Lambda^{1}_{1}=\frac{1}{\tau}##
##\Lambda^{1}_{2}=0=\Lambda^{2}_{1}##
So
##h'_{11}=h_{cd}\Lambda^{c}_{1}\Lambda^{d}_{1}=h_{11}\Lambda^{1}_{1}\Lambda^{1}_{1} =-\tau^2 / \tau^2=-1 ##
Now I am a bit confused with ##h'_{22}##, so to recover the Minkowski metric I need this to be ##1##.
I have
##h'_{22}=h_{cd}\Lambda^{c}_{2}\Lambda^{d}_{2}=h_{22}\Lambda^{2}_{2}\Lambda^{2}_{2} = \Lambda^{2}_{2}\Lambda^{2}_{2} ##
Now I have both ##X^2=X'^2=1## , so what is ##\Lambda^2_2=\frac{\partial x^{2}}{\partial x'_2}=\frac{0}{0}##, i.e how do we get ##1## for this, ##\Lambda^2_2=1##? how should this be formally done?
Many thanks in advance.