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tedpark1212
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Can anyone help me check my work for #4? I had trouble solving #4 but made an attempt. Please advise.
3. Suppose you want to show the significance of an effect size of 0.20 between your sample mean and a hypothesized mean. You intend to conduct a two-sided one-sample t-test. The sample variance is σ2 = 1.0. You assume that the population is large, or effectively infinite. If you want the test to have a power of 0.80, what is the required sample size for the following?
• A level of significance of α = 0.05
n = 2 σ2 (Z (beta) + Z (alpha/2)) 2/ effect size2
z(beta) = 1.28, z(alpha) = 1.96 for two-sided test at a level of significance of 0.05
n = 2(1) ( 1.28 + 1.96) 2/ 0.202------ for α = 0.05
n = 2 (20.9952) / 0.04
n=524.88
n= 525
The required sample size for a level of significance of α = 0.05 is 525.
• A level of significance of α = 0.01
n = 2 σ2 ( Z (beta) + Z (alpha/2) ) 2/ effect size2
z(beta) = 1.28, z(alpha) = 2.575 at a level of significance of 0.01
n = 2(1) ( 1.28 + 2.575) 2/ 0.202------ for α = 0.01
n= 2 (14.86) / 0.04
n=743.05
n= 743
The required sample size for a level of significance of α = 0.01 is 743.
4. After some research, you determine that the size of the population is N = 350. If you want the test to have a power of 0.80, what is the required sample size for the following?
A level of significance of α = 0.05
n = σ2 (Qe-1 + Qc-1 ) (Z(alpha) + Z(beta) 2 / μ₁²
n = 1(4) (1.645 + 1.282) 2 / (0.20)2
n = 856.7
n= 857
The required sample size for a level of significance of α = 0.05 is 857.
A level of significance of α = 0.01
n = σ2 (Qe-1 + Qc-1 ) (Z(alpha) + Z(beta) 2 / μ₁²
n = 1(4) (2.33 + 1.282) 2 / (0.20) 2
n= 1304.6
n= 1305
The required sample size for a level of significance of α = 0.01 is 1305.
3. Suppose you want to show the significance of an effect size of 0.20 between your sample mean and a hypothesized mean. You intend to conduct a two-sided one-sample t-test. The sample variance is σ2 = 1.0. You assume that the population is large, or effectively infinite. If you want the test to have a power of 0.80, what is the required sample size for the following?
• A level of significance of α = 0.05
n = 2 σ2 (Z (beta) + Z (alpha/2)) 2/ effect size2
z(beta) = 1.28, z(alpha) = 1.96 for two-sided test at a level of significance of 0.05
n = 2(1) ( 1.28 + 1.96) 2/ 0.202------ for α = 0.05
n = 2 (20.9952) / 0.04
n=524.88
n= 525
The required sample size for a level of significance of α = 0.05 is 525.
• A level of significance of α = 0.01
n = 2 σ2 ( Z (beta) + Z (alpha/2) ) 2/ effect size2
z(beta) = 1.28, z(alpha) = 2.575 at a level of significance of 0.01
n = 2(1) ( 1.28 + 2.575) 2/ 0.202------ for α = 0.01
n= 2 (14.86) / 0.04
n=743.05
n= 743
The required sample size for a level of significance of α = 0.01 is 743.
4. After some research, you determine that the size of the population is N = 350. If you want the test to have a power of 0.80, what is the required sample size for the following?
A level of significance of α = 0.05
n = σ2 (Qe-1 + Qc-1 ) (Z(alpha) + Z(beta) 2 / μ₁²
n = 1(4) (1.645 + 1.282) 2 / (0.20)2
n = 856.7
n= 857
The required sample size for a level of significance of α = 0.05 is 857.
A level of significance of α = 0.01
n = σ2 (Qe-1 + Qc-1 ) (Z(alpha) + Z(beta) 2 / μ₁²
n = 1(4) (2.33 + 1.282) 2 / (0.20) 2
n= 1304.6
n= 1305
The required sample size for a level of significance of α = 0.01 is 1305.