Struggling with the Shell Method in Calculus?

In summary: So for this problem, p(y) would be 8-y and the limits of integration would be from 0 to 8. In summary, the student is struggling to understand the shell method for solving volume problems and is seeking clarification on how to find the limits of integration and the purpose of y=x in the equation. They have graphed the first problem on a calculator but are advised to sketch a more useful graph on paper. The expert explains that the shell method involves calculating the volume of a typical element and adding them together, similar to taking apart an onion. For the first problem, the area element is Δy by x and is revolved around the line y=8, creating a "shell" with radius
  • #1
mathnoobie
63
0

Homework Statement


So I'm completely confused on how to solve shell method problems. I think understand it, and then there's a problem that shows that I do not understand it at all. So I want to start basic

When you're the following :
rotated about the x-axis
#1)

y=x^3
x=0
y=8

2)x+y=4
y=x
y=0



Homework Equations


2∏∫p(y)h(y)dy


The Attempt at a Solution


1) So I solve for x and get x=cubert(y)
Now what?
I want to know why I would plug in Y for the radius, and how do I find the limits of integration from this? It seems that sometimes you just plug in Y and sometimes it's some long equation.

2) Again, I solve for X, so h(x)=4-y and once again am stumped on what to do next, how do I know what p(x) is and what the limits of integration are. I don't know what purpose y=x serves and what y=0 serves.
 
Physics news on Phys.org
  • #2
mathnoobie said:

Homework Statement


So I'm completely confused on how to solve shell method problems. I think understand it, and then there's a problem that shows that I do not understand it at all. So I want to start basic

When you're the following :
rotated about the x-axis
#1)

y=x^3
x=0
y=8

2)x+y=4
y=x
y=0



Homework Equations


2∏∫p(y)h(y)dy


The Attempt at a Solution


1) So I solve for x and get x=cubert(y)
Now what?
I want to know why I would plug in Y for the radius, and how do I find the limits of integration from this? It seems that sometimes you just plug in Y and sometimes it's some long equation.
Did you sketch a graph of the function, and another of the solid of revolution? Students often skip these steps, thinking that they are extra work, but they usually make the difference between being able to work the problem and getting hopelessly lost.

For this problem, I would be more inclined to use disks - do you have to use shells?

To answer your question, you don't just "plug in" y in this problem. As you can see from your sketch (you have one, right?) the radius is the distance from the line y = 8 to the curve.
mathnoobie said:
2) Again, I solve for X, so h(x)=4-y and once again am stumped on what to do next, how do I know what p(x) is and what the limits of integration are. I don't know what purpose y=x serves and what y=0 serves.
 
  • #3
Yes, unfortunately I have to use the shell method.
And I graphed #1 on my calculator(I always graph, problem is I don't understand everything it means when it comes to the shell method), but it doesn't help me understand what happens and why.

I missed class the day of the shell method and I can't seem to grasp it just by examining the book.
 
  • #4
The shell method can be thought of as calculating the volume of a typical element, and then adding all those bits up to get the total volume. It's sort of like taking an onion apart.

I'm not sure that graphing on a calculator is the best way to go about it, since the calculator can't draw in the shells or disks or whatever. I would advise using the calculator to get the basic graph, and then sketching a more useful graph on paper.

For this problem (#1), using the shells method, you have an area element whose dimensions are Δy by x, so its area is x Δy. This area is revolved around the line y = 8, and that sweeps out a "shell". Sketch this shell and find the radius that is used in the formula you showed.
 
  • #5
Ah, I understand now. Thank you
 

FAQ: Struggling with the Shell Method in Calculus?

1.

What is the shell method and how does it work?

The shell method is a mathematical technique used to find the volume of a solid of revolution. It involves breaking down the solid into infinitesimally thin cylindrical shells and adding up their volumes using integration. This method is often used to solve problems involving rotating a 2D shape around an axis to create a 3D object.

2.

What are the steps to solving a shell method problem?

The steps to solving a shell method problem are as follows:
1. Identify the axis of rotation and the boundaries of integration.
2. Determine the radius or height of the cylindrical shells.
3. Set up the integral to calculate the volume of each shell.
4. Integrate the function and evaluate the integral.
5. Add up the volumes of all the shells to find the total volume.
6. Label the answer with appropriate units.

3.

What is the difference between the shell method and the disk method?

The shell method and the disk method are two techniques used to find the volume of a solid of revolution. The main difference between them is that the shell method uses cylindrical shells to find the volume, while the disk method uses circular disks. The shell method is typically used for more complex shapes, while the disk method is used for simpler shapes with a defined axis of rotation.

4.

Can the shell method only be used for solids of revolution?

Yes, the shell method is specifically designed to find the volume of solids of revolution. This means that the shape must be created by rotating a 2D shape around an axis. If this requirement is not met, the shell method cannot be used and an alternative method, such as the disk method, may need to be used.

5.

How can I check if my answer to a shell method problem is correct?

One way to check if your answer is correct is to use a different method, such as the disk method, to calculate the volume. If both methods yield the same result, then your answer is likely correct. You can also use online calculators or graphing software to visualize the shape and compare it to your calculated volume. Additionally, double-checking your calculations and units can help identify any errors in your solution.

Back
Top