- #1
brendan_foo
- 65
- 0
Hi guys,
In an attempt to solve the following differential equation, I have come up with an integral that has stumped me.
The differential equation is as follows:
[tex]
\frac{dy}{dx} + \frac{y}{x^2} = 2x [/tex]
Using an integrating factor, I end up with the following:
[tex] y \cdot e^{-\frac{1}{x}} = 2\int xe^{-\frac{1}{x}} dx [/tex]
I cannot solve that right hand integral, I have tried using parts and substitution and I can't really yield anything meaningful... Is it possible to evaluate this integral using basic calculus methods? Or is something else required?
Thanks!
In an attempt to solve the following differential equation, I have come up with an integral that has stumped me.
The differential equation is as follows:
[tex]
\frac{dy}{dx} + \frac{y}{x^2} = 2x [/tex]
Using an integrating factor, I end up with the following:
[tex] y \cdot e^{-\frac{1}{x}} = 2\int xe^{-\frac{1}{x}} dx [/tex]
I cannot solve that right hand integral, I have tried using parts and substitution and I can't really yield anything meaningful... Is it possible to evaluate this integral using basic calculus methods? Or is something else required?
Thanks!