Sturm-Liouville confusion

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In summary, the conversation discusses the concept of Hermitian operators and their application to the differential operator L acting on the vector space V of functions. It is noted that L is Hermitian if the boundary condition [u*(x)p(x)dv/dx]ab=0 is satisfied for all functions u and v in V. An example of this is given, where the eigenfunctions are found to be exp[(√λn)x] and exp[-(√λn)x] with quantized eigenvalues of λn=-n2. It is clarified that the eigenfunctions form a complete basis for the vector space V and any function can be written as a sum of eigenfunctions.
  • #1
fayled
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So the basic idea is that the differential operator acting on the vector space V of functions f:[a,b]->ℂ, with some weight function w(x)
L≡d/dx[p(x)d/dx]+q(x)
is Hermitian (self-adjoint) if we have that for any two functions u(x), v(x) in this vector space,
[u*(x)p(x)dv/dx]ab=0,
thus L has real eigenvalues and it's eigenfunctions form an orthonormal basis for V.

Now my notes seem to be suggesting to me that if we write the SL problem, i.e the eigenvalue equation
Lennen
for eigenfunctions en and eigenvalues λn, then so long as the eigenfunctions satisfy the above boundary condition, i.e [en*(x)p(x)dem/dx]ab=0, then L is Hermitian. This is confusing me because as I stated above, I'm sure this boundary condition must apply for all u,v in the space of functions V, not just the eigenfunctions.

There is an example of this form given, which is
d2endx2=λnen.
It finds the eigenfunctions as exp[(√λn)x] and exp[-(√λn)x] where the eigenvalues are yet to be determined. Then it says let our interval be [a,b]=[-π,π] and so because p(x)=1, it asks for [e*mden/dx]π=0 (for any combination of the eigenfunctions), which quantizes the eigenvalues as λn=-n2 for integer n. However again, as I said above, we are only asking for the eigenfunctions to satisfy this boundary condition, whilst I was under the impression that any two functions, u,v in the space V (which does include, but is not limited to, pairs of the eigenfunctions) must meet this condition, not just the eigenfunctions.

Could anyone clear this up for me? Thankyou in advance :D
 
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  • #2
Note the example should be d2en/dx2nen. Anybody please?
 
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I believe it's the case that the vector space on which L acts is determined by the boundary conditions you place on the problem. Given this, you solve the SL problem and obtain a set of eigenfunctions which form a complete basis for that vector space. So it follows that any function can be written as a sum of eigenfunctions. I hope that makes sense.
 
  • #5


I would like to clarify that the Sturm-Liouville problem involves finding the eigenvalues and eigenfunctions of a differential operator, which is Hermitian if it satisfies the boundary condition [u*(x)p(x)dv/dx]ab=0 for all functions u,v in the vector space V. This condition ensures that the eigenvalues are real and the eigenfunctions form an orthonormal basis for V.

In the given example, the eigenfunctions are found to be exp[(√λn)x] and exp[-(√λn)x] and the eigenvalues are quantized as λn=-n2 for integer n. This condition is satisfied for all functions in V, not just the eigenfunctions.

It is important to note that the boundary condition is necessary for the Hermiticity of the differential operator, but it does not necessarily determine the eigenvalues and eigenfunctions. They still need to be solved for using the eigenvalue equation Len=λnen.

I hope this clarifies any confusion and helps in understanding the Sturm-Liouville problem.
 

FAQ: Sturm-Liouville confusion

1. What is Sturm-Liouville confusion?

Sturm-Liouville confusion is a common issue encountered in solving differential equations using the Sturm-Liouville method. It refers to the difficulty in determining the correct boundary conditions and eigenvalues in the process.

2. Why is Sturm-Liouville confusion a problem?

Sturm-Liouville confusion can be problematic because it can lead to incorrect solutions or a lack of solutions altogether. This can greatly affect the accuracy and validity of the results obtained from the differential equation model.

3. How does Sturm-Liouville confusion arise?

Sturm-Liouville confusion can arise due to various factors such as improper choice of boundary conditions, non-uniqueness of solutions, or errors in the calculation of eigenvalues. It can also occur when the differential equation being solved does not satisfy the conditions required for the Sturm-Liouville method.

4. What are some strategies to avoid Sturm-Liouville confusion?

One strategy is to carefully choose the boundary conditions and ensure that they are consistent with the physical problem being modeled. It is also important to verify the uniqueness of solutions and check for any errors in the calculation of eigenvalues. Using alternative methods or software packages can also help in avoiding Sturm-Liouville confusion.

5. How can Sturm-Liouville confusion be resolved?

Resolving Sturm-Liouville confusion often involves identifying the source of the problem and making necessary adjustments to the boundary conditions or eigenvalues. In some cases, it may be necessary to use other methods of solving differential equations. Consulting with experts or seeking guidance from literature can also help in resolving Sturm-Liouville confusion.

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