- #1
Yazan975
- 30
- 0
View attachment 8419
What I have done:
I changed all fractions to common denom and that gave me
5y-5x=1 (1) *I numbered the fractions
5y+2x=5 (2)
Then: 5y=5-2x
Substitute into equation 1
(5-2x)-5x=1
5-7x=1
x=4/7
Thing is my answer says I should be getting x=0
Any hints?
What I have done:
I changed all fractions to common denom and that gave me
5y-5x=1 (1) *I numbered the fractions
5y+2x=5 (2)
Then: 5y=5-2x
Substitute into equation 1
(5-2x)-5x=1
5-7x=1
x=4/7
Thing is my answer says I should be getting x=0
Any hints?