- #1
Looh
- 6
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Hello!
I'm having trouble subtracting two equations, I'm not really sure how to go about it.
[itex]\\
\frac{4\pi r^3}{3}(\rho_1 - \rho_2)g - 6\pi r\eta v_0 = 0\\
\frac{4\pi r^3}{3}(\rho_1 - \rho_2)g - 6\pi r\eta v_1 - qE = 0[/itex]
For clarification, there are three different equations used.
[itex]\\
F_g = \frac{4\pi r^3}{3}(\rho_1 - \rho_2)g \\
F_f = 6\pi r\eta v_0\\
F_e = qE
[/itex]
Which gives:
[itex]\\
F_g - F_f = 0 \\
F_g - F_f - F_e = 0
[/itex]
This, in turn, results in [itex]F_e[/itex], or [itex]qE[/itex], but I'm sure that's wrong.How should I go about solving this?Thanks in advance.
I'm having trouble subtracting two equations, I'm not really sure how to go about it.
[itex]\\
\frac{4\pi r^3}{3}(\rho_1 - \rho_2)g - 6\pi r\eta v_0 = 0\\
\frac{4\pi r^3}{3}(\rho_1 - \rho_2)g - 6\pi r\eta v_1 - qE = 0[/itex]
For clarification, there are three different equations used.
[itex]\\
F_g = \frac{4\pi r^3}{3}(\rho_1 - \rho_2)g \\
F_f = 6\pi r\eta v_0\\
F_e = qE
[/itex]
Which gives:
[itex]\\
F_g - F_f = 0 \\
F_g - F_f - F_e = 0
[/itex]
This, in turn, results in [itex]F_e[/itex], or [itex]qE[/itex], but I'm sure that's wrong.How should I go about solving this?Thanks in advance.
Last edited: