- #1
jk22
- 729
- 24
If we consider a bipartite system as in EPRB experiment we get the probabilities :
p(++)=p(--)=1/4*(1-cos(theta))
p(+-)=p(-+)=1/4*(1+cos(theta))
p(+A)=p(+B)=p(-A)=p(-B)=1/2
Thus the sum of all the probabilities equals 3...
How does that come ? Is it because in fact there are only double events out of which we consider the averages of A and B sides too, thus making 3 sample set out of one experiment ?
p(++)=p(--)=1/4*(1-cos(theta))
p(+-)=p(-+)=1/4*(1+cos(theta))
p(+A)=p(+B)=p(-A)=p(-B)=1/2
Thus the sum of all the probabilities equals 3...
How does that come ? Is it because in fact there are only double events out of which we consider the averages of A and B sides too, thus making 3 sample set out of one experiment ?
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