- #1
riseofphoenix
- 295
- 2
Number 11)
This is what I did:
Ʃτ = F2r2 + F1r1 = 0
(195)(7) + F1(0.7) = 0
F1(0.7) = -(195)(7)
F1 = -1365/0.7
F1 = -1950 N
F1 = 1950 N
Is that answer right?
Number 12)
This is what I did:
Since this is a massless rod and the location of the axis is through the end, I = ML2
Linitial = Lfinal (Conservation of Angular Momentum)
(I1ω1 + I2ω2)initial = (I1ω1 + I2ω2)final
[ M1L12ω1 ] + [ M2L22ω2 ] = [ M1L12ω1 ] + [ M2L22ω2 ]
[ (14 kg)(4)2(6) ] + [ (2 kg)(10)2(6) ] = [(14 kg)(10)2(ω2) ] + [ (2 kg)(4)2(ω2) ]
1344 + 1200 = 1400(ω2) + 32(ω2)
2544 = 1432(ω2)
2544/1432= ω2
1.776 = ω2
1.78 rad/s = ω2
Is that right?
Number 13)
I think this one is right. I googled it...
Number 14)
fobserver = fsource [ (v + vobserver)/(v + vsource) ]
fobserver = 1550 [ (340 + 9 m/s)/(340 + 24 m/s) ]
fobserver = 1550(349/364)
fobserver = 1550(0.958791209)
fobserver = 1486 Hz
Is that right?
This is what I did:
Ʃτ = F2r2 + F1r1 = 0
(195)(7) + F1(0.7) = 0
F1(0.7) = -(195)(7)
F1 = -1365/0.7
F1 = -1950 N
F1 = 1950 N
Is that answer right?
Number 12)
This is what I did:
Since this is a massless rod and the location of the axis is through the end, I = ML2
Linitial = Lfinal (Conservation of Angular Momentum)
(I1ω1 + I2ω2)initial = (I1ω1 + I2ω2)final
[ M1L12ω1 ] + [ M2L22ω2 ] = [ M1L12ω1 ] + [ M2L22ω2 ]
[ (14 kg)(4)2(6) ] + [ (2 kg)(10)2(6) ] = [(14 kg)(10)2(ω2) ] + [ (2 kg)(4)2(ω2) ]
1344 + 1200 = 1400(ω2) + 32(ω2)
2544 = 1432(ω2)
2544/1432= ω2
1.776 = ω2
1.78 rad/s = ω2
Is that right?
Number 13)
I think this one is right. I googled it...
Number 14)
fobserver = fsource [ (v + vobserver)/(v + vsource) ]
fobserver = 1550 [ (340 + 9 m/s)/(340 + 24 m/s) ]
fobserver = 1550(349/364)
fobserver = 1550(0.958791209)
fobserver = 1486 Hz
Is that right?
Last edited: