Sumation of symmetric and skew symmetri metrices

  • Thread starter Thread starter harshakantha
  • Start date Start date
  • Tags Tags
    Symmetric
Click For Summary
The discussion focuses on expressing a given matrix as the sum of a symmetric and a skew-symmetric matrix. Initially, the user incorrectly defined the symmetric and skew-symmetric matrices, leading to an incorrect sum. After clarification, it was noted that the correct approach involves using the formula A = (A + A')/2 for the symmetric part and A = (A - A')/2 for the skew-symmetric part, where A' is the transpose of the matrix A. This method allows for the correct identification of the symmetric and skew-symmetric components of the original matrix. The final consensus confirms that this formula is indeed correct for the task.
harshakantha
Messages
41
Reaction score
0
Express \left(\begin{array}{cccc}
6 & 1 & 5\\
-2 & -5 & 4\\
-3 & 3 & -1\
end{array}
\right) as the sum of the symmetric and skew symmetric matrices.

I did this following way

Consider symmetric metric as "A"
then;
A = \left(\begin{array}{cccc}
6 & 1 & 5\\
1 & -5 & 4\\
5 & 4 & -1\
\end{array}
\right)

Consider skew symmetric metric as "B"
then;
B = \left(\begin{array}{cccc}
0 & 1 & 5\\
-1 & 0 & 4\\
-5 & -4 & 0\
\end{array}
\right)

Then sum of matrices A and B is;
A+B= \left(\begin{array}{cccc}
6 & 2 & 10\\
0 & -5 & 8\\
0 & 0 & -1\
\end{array}
\right)

is this correct??:smile:
 
Physics news on Phys.org
Fixing your LaTeX...
harshakantha said:
Express
\begin{pmatrix}
6 & 1 & 5 \\
-2 & -5 & 4 \\
-3 & 3 & -1
\end{pmatrix}
as the sum of the symmetric and skew symmetric matrices.

I did this following way

Consider symmetric metric as "A"
then;
A = \begin{pmatrix}<br /> 6 &amp; 1 &amp; 5 \\ <br /> 1 &amp; -5 &amp; 4 \\ <br /> 5 &amp; 4 &amp; -1 <br /> \end{pmatrix} <br />
Consider skew symmetric metric as "B"
then;
<br /> B = \begin{pmatrix}<br /> 0 &amp; 1 &amp; 5 \\ <br /> -1 &amp; 0 &amp; 4 \\ <br /> -5 &amp; -4 &amp; 0<br /> \end{pmatrix} <br />

Then sum of matrices A and B is;
A+B = \begin{pmatrix}<br /> 6 &amp; 2 &amp; 10 \\ <br /> 0 &amp; -5 &amp; 8 \\ <br /> 0 &amp; 0 &amp; -1<br /> \end{pmatrix}<br />
is this correct??:smile:
No. The problem is asking you to find A and B such that A+B is equal to the original matrix. This is obviously not the case for your A and B.
 
Thank you for fixing Latex vela :smile:, oh.. I think I've understood the question wrongly, so can you give me a hint, on how to do that in correct way :smile:
 
Let's take a generic symmetric and a skewed symmetric matrix.

Say:
A=\begin{pmatrix}a &amp; b \\ b &amp; d \end{pmatrix}\qquad A=\begin{pmatrix}0 &amp; q \\ -q &amp; 0\end{pmatrix}

Adding them up will yield:
A+B=\begin{pmatrix}a &amp; b+q \\ b-q &amp; d \end{pmatrix}

You should note that the average of (b-q) and (b+q) is b.

Now can you think up how to construct a symmetric and a skewed symmetric matrix from a given matrix?
 
Thank you I like Serena, I've found a formula to express a square matrix by using symmetric and skew symmetric matrices here it is;

Let A be the given square matrix
A can be uniquely expressed as sum of a symmetric matrix and a skew symmetric matrix, which is

A =(A+A')/2 + (A-A')/2 consider A' is Transpose of matrix A;
by using this I was able to got the symmetric matrix and a skew symmetric matrix for the given matrix.:smile:. is this correct?
 
Yes, this this correct.
 
The book claims the answer is that all the magnitudes are the same because "the gravitational force on the penguin is the same". I'm having trouble understanding this. I thought the buoyant force was equal to the weight of the fluid displaced. Weight depends on mass which depends on density. Therefore, due to the differing densities the buoyant force will be different in each case? Is this incorrect?

Similar threads

  • · Replies 4 ·
Replies
4
Views
1K
  • · Replies 13 ·
Replies
13
Views
2K
  • · Replies 4 ·
Replies
4
Views
2K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 7 ·
Replies
7
Views
2K
Replies
5
Views
1K
  • · Replies 3 ·
Replies
3
Views
3K
  • · Replies 1 ·
Replies
1
Views
1K
  • · Replies 8 ·
Replies
8
Views
2K
  • · Replies 1 ·
Replies
1
Views
2K