- #1
gmmstr827
- 86
- 1
Calculate the summation of i=1 to inf of the summation of j=i to inf of p^(j+i).
Yes, it is the summation of a summation. p^(j+i) can be separated into (p^j)*(p^i).
Yes, it is the summation of a summation. p^(j+i) can be separated into (p^j)*(p^i).